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nordsb [41]
2 years ago
8

Assume the availability of a method named makeStars that can be passed a non-negative integer n and that returns a String of n a

sterisks. Write a method named printTriangle that receives a non-negative integer n and prints a triangle of asterisks as follows: first a line of n asterisks, followed by a line of n-1 asterisks, and then a line of n-2 asterisks, and so on.
Mathematics
1 answer:
kramer2 years ago
6 0

Answer:b

Step-by-step explanation:

b

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Triangle E F G is shown. Which statements regarding Triangle E F G are true? Select three options. E F + F G greater-than E G E
Leokris [45]

Answer:

options 1 ( E F + F G greater-than E G ), 2 (E G + F G greater-than E F ) and 5 ( E G + E F less-than F G ) are true.

Step-by-step explanation:

Given triangle EFG.

In each tirangle with sides lengths a, b and c, we always have

a+b>c\\ \\a+c>b\\ \\b+c>a

In triangle EFG:

  • EF+FG>EG;
  • EG+GF>EF;
  • FE+EG>FG.

So, options 1 ( E F + F G greater-than E G ), 2 (E G + F G greater-than E F ) and 5 ( E G + E F less-than F G ) are true.

Options 3 and 4 are false.

4 0
2 years ago
Read 2 more answers
Mary wrote a book of 1536 pages. She numbered all pages by hand. How many times did she write the digit 6?
Usimov [2.4K]

Answer:

404 times

Step-by-step explanation:

8 0
2 years ago
Ratio for 669 and 221
alexandr402 [8]

Hello from MrBillDoesMath!

Answer:

669/221

Discussion:

Ratio of 669 to 221 =  669/221.

Now,  669 = 3 * 223 and 221  = 13 * 17. Note that all numbers involved in the factorizations are distinct primes so nothing cancels out in their ratio. That is,

669/221 can not be reduced further.


Thank you,

MrB

5 0
2 years ago
Read 2 more answers
Terrence solves the problem and finds 53.04 x 4.6 = 2,439.84. Tara says that his product is incorrect. Fill in the blanks to hel
Burka [1]
Tara was right terrence was close but he put the(.) in the wrong spot the correct answer is 243.984 but terrence put 2439.84
                         ^                                             ^
                          l                                              l
                          l                                              l
7 0
2 years ago
Find all the zeros of the equation 12x^2-64=-x^4
Natalija [7]

Answer: all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

Step-by-step explanation:

Since we  have given that

12x^2-64=-x^4\\\\x^4+12x^2-64=0

We need to find the zeroes of the above equation.

So, we will use  "Split the middle terms" :

x^4+12x^2-64=0\\\\x^4+16x^2-4x^2-64=0\\\\x^2(x^2-16)-4(x^2-16)=0\\\\(x^2-4)(x^2-16)=0\\\\x^2-4=0\ or\ x^2-16=0\\\\\text{ "Using }a^2-b^2=(a+b)(a-b)"\\\\x^2-4=x^2-2^2=(x-2)(x+2)\\\\x^2-16=x^2-4^2=(x+4)(x-4)

So, all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

7 0
2 years ago
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