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katovenus [111]
2 years ago
13

Alison was looking at a tissue under the microscope. It had cells within lacuna and the matrix was glassy looking. What type of

tissue is she looking at? ? Group of answer choices
Physics
1 answer:
Leokris [45]2 years ago
5 0

Answer:

  • There are a number of body cells that are composed of a way different components or we can say elements, as there are bone cells know to be more brittle or we can say less flexible as compared to the cartilaginous cells inside the human body's structure. While, the different cells are name differently by the scientists or the professionals who worked on them. Such as the osteoblasts are the bone cells which are composed of very rigid and dense form of matrix inside its structure, this provides the rigidness to the whole body structure of the living beings body.
  • Alison was looking at a tissue under the microscope. It had cells within lacuna and the matrix was glassy looking, he was thus observing <u>the chondrocytes(the cartilaginous cells inside the animal body).</u>
  • While, there are different connective tissues which mainly functions to provide a more connected form of body structure, and the organs are well organized by the connective tissues which brings texture and connective to one another. While, the more flexible form of body cells the chondrocytes are there to enhance the development of the cartilaginous structure inside the living body. As, the provide the required flexibility to the body structure to move more freely and perform locomotion in the desired angle and direction.

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A certain slide projector has a 100 mm focal length lens. How far away is the screen, if a slide is placed 103 mm from the lens
Vlad [161]

Answer:

3.43 m

Explanation:

f = 100 mm

u = - 103 mm

Let v be the distance between the screen and the lens of the projector.

Use lens equation

1 / f = 1 / v - 1 / u

1 / 100 = 1 / v + 1 / 103

1 / v = 1 / 100 - 1 / 103

1 / v = (103 - 100) / (100 x 103)

1 / v = 3 / 10300

v = 3433.33 mm = 3.43 m

4 0
2 years ago
Two stones resembling diamonds are suspected of being fakes. To determine if the stones might be real, the mass and volume of ea
dimaraw [331]

Answer:

stone A is diamond.

Explanation:

given,

Volume of the two stone =  0.15 cm³

Mass of stone A = 0.52 g

Mass of stone B = 0.42 g

Density of the diamond =  3.5 g/cm³

So, to find which stone is gold we have to calculate the density of both the stone.

We know,

density\density = \dfrac{mass}{volume}

density of stone A

\rho_A = \dfrac{0.52}{0.15}

\rho_A = 3.467\ g/cm^3

density of stone B.

\rho_B = \dfrac{0.42}{0.15}

\rho_B = 2.8\ g/cm^3

Hence, the density of the stone A is the equal to Diamond then stone A is diamond.

6 0
2 years ago
You are installing a new spark plug in your car, and the manual specifies that it be tightened to a torque that has a magnitude
klemol [59]
We are given 

the torque requirement of 97 Newton meter. 

The formula of the torque is

τ = r * F * sinθ

where 

τ is the torque
r = radius from the axis of rotation to the point of application. 
F = force exerted 
θ = the angle between the lever arm and the radius

Try to substitute the given and solve for F. 
5 0
2 years ago
An automobile approaches a barrier at a speed of 20 m/s along a level road. The driver locks the brakes at a distance of 50 m fr
AleksAgata [21]

Answer:

μ = 0.408

Explanation:

given,

speed of the automobile (u)= 20 m/s

distance = 50 m

final velocity  (v) = 0 m/s

kinetic friction = ?

we know that,

v² = u² + 2 a s

0 = 20² + 2 × a × 50

a = \dfrac{400}{2\times 50}

a = 4 m/s²

We know

F = ma = μN

ma = μ mg

a = μ g

\mu = \dfrac{a}{g}

\mu = \dfrac{4}{9.81}

μ = 0.408

hence, Kinetic friction require to stop the automobile before it hit barrier is 0.408

5 0
2 years ago
The box leaves position x=0x=0 with speed v0v0. The box is slowed by a constant frictional force until it comes to rest at posit
const2013 [10]

Answer:

fr = ½ m v₀²/x

Explanation:

This exercise the body must be on a ramp so that a component of the weight is counteracted by the friction force.

The best way to solve this exercise is to use the energy work theorem

            W = ΔK

Where work is defined as the product of force by distance

           W = fr x cos 180

The angle is because the friction force opposes the movement

          Δk =K_{f} –K₀

          ΔK = 0 - ½ m v₀²

We substitute

         - fr x = - ½ m v₀²      

           fr = ½ m v₀²/x

8 0
2 years ago
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