C. Sedimentary Layers, sedimentary rocks are created as a result of high pressure :)
I hope this helped!
Answer:
Small intestine, liver, bile and lipase.
Explanation:
Digestion of fat occurs in the small intestine. Its digestion occurs with the help of bile, that is made in the liver. Bile breaks the fat into small drops that are easier for the lipase enzymes to change it. Lipase enzymes is a type of enzymes that works only on lipids and lipids are broken down into fatty acids and glycerol. These substances are absorbed by our body and used it for producing ATP for the body.
Answer:
plant: This Elodea leaf cell exemplifies a typical plant cell. It has a nucleus, and a stiff cell wall which gives the cell its box-like shape. The numerous green chloroplasts allow the cell to make its own food (by photosynthesis).
The central vacuole takes up most of the volume of the cell. It is transparent, but you can see where it's pressing the chloroplasts up against the cell wall, especially at the ends of the cell.
Like animal cells, the cytoplasm of this plant cell is bordered by a cell membrane. The membrane is so thin and transparent that you can't see it, but it is pressed against the inside of the cell wall.
animal :This human cheek cell is a good example of a typical animal cell. It has a prominent nucleus and a flexible cell membrane which gives the cell its irregular, soft-looking shape.
Like most eukaryotic cells, this cell is very large compared to prokaryotic cells. For scale, notice the pair of dark blue bacteria cells sticking to the right edge of the cheek cell. The bacteria are only a fraction of the size of the nucleus, but their tiny size is typical for bacteria.
Answer:C. Point, nonpoint
Explanation:
Point source of water pollution originate from a single source and the source of origin can be determined. Industrial and sewage drainage systems are the examples of point source pollutants. The source of pollutant is easy to detect and monitor.
Non-point source of water pollution the source of pollution remains undetermined. The pollutants may enter in water body through multiple sources. Hence, it is difficult to track back the source of single pollutant. Thus non-point source pollution cannot be clean and monitored.
<span> Wow, this is a big question, but here goes. Freckles q: 1) Since freckles is the dominant phenotype, this means that Olivia must have the recessive phenotype, which is only given by the genotype ff. FF and Ff would both give freckles because, again, freckles is dominant. So any genotype with F_ would give freckles. 2)Same answer as #1. 3) Since they only have f alleles to pass on, both the dad and the mom will pass on one f each to 100% of their children. So all will have genotype ff and no freckles.
Hairline q: Since the parents are heterozygous, this means that their genotype has one of each allele to give Hh. (Even though you said they are quadruplets, I'm going to assume they are fraternal (different DNA) b/c otherwise they'd always have the same genotype if they are identical). 1) Okay, so when you do the Punnett square for Hh x Hh, you'll get 1HH:2Hh:1hh. Since widow's peak is dominant, any genotype with H_ gives the widow's peak. So, there are 3 options from the Punnett square, so you'll have 3 of the kids with widow's peak. Theres a 3/4 chance that a child will have widow's peak from these parents. 2) Since straight hairline is recessive, you need hh to get this phenotype and there is only one option. So, there will only be one child with the straight hairline. (1/4 chance). 3) Homozygous dominant means that you have two of the dominant allele, so HH. Since there is only 1 option, there is only one child with this genotype.
Tongue q: Since rolling the tongue is a dominant trait and the parents both can't roll their tongues, they must have a homozygous recessive genotype for this to happen (remember in dominance, any genotype with a dominant allele will give the dominant phenotype), so they have tt. 1) Since again they can only pass on t alleles, the kids will all have tt, so no one can roll their tongues. 2) None of them are hybrids because there was no variety in the genotypes or anything. Both parents had tt, so they were same in genotype. 3) She will have tt because of the above stated reasons.
Dimples q: Since all four kids have dimples, the dominant phenotype, they must all have the genotype D_ (either Dd or DD). 1) Since Marcus is a hybrid, this means that he had parents that were DD x dd to give him the genotype Dd. Since he has a recessive allele d in his genotype, Olivia must have all dominant alleles to make sure that each child has at least one dominant D. So, she must have the genotype DD. 2) Since she is DD, the dominant alleles will make her have dimples.
Earlobe q: 1) Since the parents are EE both, a cross of EE x EE will give EE genotype children. So, all children have EE, this means they all have free earlobes. So the ratio is 100% free to 0% attached earlobes. 2)Homozygous means they have two of the same alleles. Since all of them have EE, 100% of them are homozygous.
PTC q: Marcus has genotype bb and Olivia has genotype Bb because she is heterozygous. 1) The cross of bb x Bb gives 1Bb:1bb, So, 1/2 can taste the paper, so 50% can taste. 2) Since Violet can't taste the paper, she must be recessive and have the genotype bb. Since both of the boys can taste, they must have the genotypes Bb. Since 1/2 is already Bb, Claudia must be bb to help create the 50% that can't taste in the kids. 3)So, 2 people out of the family can taste the paper. Even though Olivia has Bb and should be able to taste, she can't. So, only Jonas and Nathan can taste the paper.
Pheww... done.. Hope this helps! :)<span>
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