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Inessa05 [86]
2 years ago
4

The equilibrium fraction of lattice sites that are vacant in gold at 800°C is 2.5 × 10-5. Calculate the number of vacancies (per

meter cubed) at 800 °C. Assume a density of 18.45 g/cm3 for Au (at 800 °C).
Engineering
1 answer:
lakkis [162]2 years ago
8 0

Answer:

The number of vacancies (per meter cube) = 1.41E24 /m³

Explanation:

Given

p = Density of Gold (Au) = 18.45 g/cm³ ----- convert to g/m³

18.45 g/cm³ = 18.45 g/cm³ * 10^6 cm³/m³

= 18.45E6 g/m³

Avogadro's Number = NA = 6.022E23 atoms/mol

Fraction of Vacant lattice of Gold = 2.5E-5

A(Au) = Atomic weight of gold = 196.96657 g/mol.

First, we'll calculate the total number of lattice sites in Gold using

NA * p/A(Au)

= 6.022E23 * 18.45E6 / 196.96657

= 5.6408506275963E28 atoms/m³

Then we multiply the resulting value by the fraction of lattice sites that are vacant in Gold to get the number of vacancies (per meter cube)

The number of vacancies (per meter cube) = 5.6408506275963E28 * 2.5E-5

The number of vacancies (per meter cube) = 1.41E24 /m³

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sp2606 [1]

Answer: 0.021818m =2.18x10^-²m

Explanation: Using Laplace principle

Design pressure is =12 bar= 1200000N/m²

T = Wall thickness

Design stress=110Mn/m²= 110,000,000N/m²

Radius= diameter/2 =4/2=2m

Design stress=Hoop stress =Pr/t where p=internal pressure or internal pressure, r=radius and t= wall thickness.

As Laplace equation stated.

110,000,000= 1,2000,00 x 2/t

t= 2,400,000/110,000,000.

t= 0.021818m

t=2.18x10^-2m.

3 0
2 years ago
An electric field is expressed in rectangular coordinates by E = 6x2ax + 6y ay +4az V/m.Find:a) VMN if point M and N are specifi
Fittoniya [83]

Answer:

a.) -147V

b.) -120V

c.) 51V

Explanation:

a.) Equation for potential difference is the integral of the electrical field from a to b for the voltage V_ba = V(b)-V(a).

b.) The problem becomes easier to solve if you draw out the circuit. Since potential at Q is 0, then Q is at ground. So voltage across V_MQ is the same as potential at V_M.

c.) Same process as part b. Draw out the circuit and you'll see that the potential a point V_N is the same as the voltage across V_NP added with the 2V from the other box.

Honestly, these things take practice to get used to. It's really hard to explain this.

3 0
2 years ago
Oliver is designing a new children’s slide to increase the speed at which a child can descend. His first design involved steel b
AVprozaik [17]

Answer:

The correct option is;

A) Steel becomes too hot in the Sun and can burn the children

Explanation:

The properties of steel includes;

Low specific heat capacity, high thermal and electrical toughness, high hardness, high tensile strength, high yield strength, appreciable elongation, high fatigue strength, can easily corrode, high malleability and ability to creep

Therefore, due to the low specific heat capacity, which is 0.511 J/(g·°C) and high conductivity of steel which is about 32 W/(m·k), the temperature of the steel can rapidly rise and the hot steel surface can readily conduct the heat, (due to the temperature difference) to other bodies that come in contact

8 0
2 years ago
CHALLENGE ACTIVITY 1.4.1: Basic syntax errors. Type the statements. Then, correct the one syntax error in each statement. Hints:
Lunna [17]

Answer:

Lets check each statement for the errors.

Explanation:

System.out.println("Predictions are hard.");

This statement has no syntax errors. When this statement is executed the following line will be displayed:

Predictions are hard.

System.out.print("Especially ');

This statement is missing the closing quotation mark. A single quotation mark is placed instead of double quotation mark in the statement.

The following error message will be displayed when this program statement will be compiled:

Main.java:15: error: unclosed string literal

String literals use double quotes. So to correct this syntax error, the statement should be changed as follows:

System.out.print("Especially");

The output of this corrected line is as following:

Especially

System.out.println("about the future.").

In this line a period . is placed at the end of the statement instead of a semicolon ; but according to the syntax rules statements should end in semicolons.

The error message displayed when this line is compiled is as following:

Main.java:15: error: ; expected

Main.java:15: error: not a statement

So in order to correct this syntax error the statement should be changed as following:

System.out.println("about the future.");    

The output of this corrected line is as following:

about the future

System.out.println("Num is: " - userName);

There is a syntax error in this statement because of - symbol used instead of +

+ symbol is used to join together a variable and a value a variable and another variable in a single print statement.

The error message displayed when this line is compiled is as following:

Main.java:13: error: bad operand types for binary operator '-'

So in order to correct this syntax error the statement should be changed as following:

System.out.println("Num is: " + userName);

This line will print two things one is the string Num is and the other is the value stored in userName variable.

So let userName= 5 then the output of this corrected line is as following:

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8 0
2 years ago
6. You are an electrician working in an industrial plant. You are building a motor control cabinet that contains six motor start
Sveta_85 [38]

Answer:

It's indeed safer to suggest a 150 VA transformer. Following table however is the clarification given.

Explanation:

For 2 motors with 0.1 A, the Power will be:

P = 2\times 120\times 0.1

  = 24 \ W

For 4 motors with 0.18 A, the Power will be:

P = 4\times 120\times 0.18

  = 86.4 \ W

As we know, for 6 pilot lamps, the power is "5 W".

So,

The total power will be:

⇒ P = 24+86.4+5

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Now,

Consider the power factor to be "0.95"

VA of transformer is:

= PF\times Power

= 115.4\times 0.9

= 109.63 \ VA

8 0
2 years ago
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