Again, suppose that n and r denote integer values where r > 0 and n ≥ 0. What are two "simple" values, say lowEnough and tooH
1 answer:
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Answer:
Here is the copy assignment operator for CarCounter:
CarCounter& CarCounter::operator=(const CarCounter& objToCopy) {
carCount = objToCopy.carCount;
return *this; }
The syntax for copy assignment operator is:
ClassName& ClassName :: operator= ( ClassName& object_name)
In the above chunk of code class name Is CarCounter and object name is objToCopy.
Assignment operator = is called which assigns objToCopy.carCount to the new objects's carCount.
This operator basically is called when an object which is already initialized is assigned a new value from another current object.
Then return *this returns the reference to the calling object
Explanation:
The complete program is:
#include <iostream> //to use input output functions
using namespace std; //to access objects like cin cout
class CarCounter { //class name
public: // public member functions of class CarCounter
CarCounter(); //constructor of CarCounter
CarCounter& operator=(const CarCounter& objToCopy); //copy assignment operator for CarCounter
void SetCarCount(const int setVal) { //mutator method to set the car count value
carCount = setVal; } //set carCount so setVal
int GetCarCount() const { //accessor method to get carCount
return carCount; }
private: //private data member of class
int carCount; }; // private data field of CarCounter
CarCounter::CarCounter() { //constructor
carCount = 0; //intializes the value of carCount in constructor
return; }
// FIXME write copy assignment operator
CarCounter& CarCounter::operator=(const CarCounter& objToCopy){
/* copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *this */
carCount = objToCopy.carCount;
return *this;}
int main() { //start of main() function
CarCounter frontParkingLot; // creates CarCounter object
CarCounter backParkingLot; // creates CarCounter object
frontParkingLot.SetCarCount(12); // calls SetCarCount method using object frontParkingLot to set the value of carCount to 12
backParkingLot = frontParkingLot; //assigns value of frontParkingLot to backParkingLot
cout << "Cars counted: " << backParkingLot.GetCarCount(); //calls accessor GetCarCount method to get the value of carCount and display it in output
return 0; }
The output of this program is:
Cars counted = 12
Answer:
(a)Applications Time Stamp Events
(b)S=0.5(W-)+
, where
≤W≤
+8.
Explanation:
Some applications assume that clocks always advance, so they could timestamp events under this assumption.
In our case we have the wrong timed clock, say W and the hardware clock H which is supposed to advance at a perfect rate.
We proceed to construct a software clock such that after 8 seconds we can replace the wrong timed clock with the software clock in good conditions.
Let us denote the software clock with S.
Then, S=c(W-)+
where:
=The current Time(10:27:54) and;
c is to be found.
We already know that S=+4 when W=
+8,
So:
S=c(W-)+
+4=c(
+8-
)+
4=8c
c=0.5
We obtain the formula
S=0.5(W-)+
, where
≤W≤
+8.