T is a linear function of C ==> T = mC + b
Each additional chirp C corresponds to an increase in T of 0.25 ==> m = 0.25
T = 52 when C = 20 ==> 52 = 0.25(20) + b ==> b = 52 - 5 = 47
So T = 0.25C + 47
When C = 100 then T = 0.25(100) + 47 = 25 + 47 = 72
When C = 120 then T = 0.25(120) + 47 = 30 + 47 = 77 so the
temperature range is between 72 and 77 when there are between 100 and
120 chirps per minute
Answer:
The answer is "8".
Step-by-step explanation:
Let the number are a, b, c then value is as follows:
a= 3
b= 5
c= 7
The addition of equation ⇒ a+b+c =15....................(i)
multiply by the value ⇒ 3a + 5b + 7c = 75
...............(ii)
let b= 15-a-c which subtract from equation (ii)
equation:
⇒ 3a + 5b + 7c = 75
⇒ 3a + 5(15-a-c) + 7c = 75
⇒ 3a +75-5a-5c+7c = 75
⇒ 3a -5a-5c+7c = 75-75
⇒ -2a + 2c = 0
⇒ 2(c-a) = 0
⇒ (c-a) = 0
⇒ c=a
if we put value in between 0 to 7 from it satisfies the two equations, with c=a and b = 15 - a - c. So, the correct answer is 8.