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Nookie1986 [14]

2 years ago

10

The average lethal blood concentration of morphine is estimated to be 2.5 µg/mL with a standard deviation of 0.95 µg/mL. The dat

a is normally distributed. Examine the range of values 0.05 to 4.95 µg/mL. Answer the following questions and provide the appropriate calculations (13 points):
a. What is the probability associated with the range lethal morphine blood levels?

1 answer:

dmitriy555 [2]2 years ago

5 0

Answer:

The probability associated with the range lethal morphine blood levels is 0.9902.

Step-by-step explanation:

Let <em>X</em> = lethal blood concentration of morphine.

The random variable <em>X</em> is normally distributed with parameter <em>μ</em> = 2.5 μg/ mL and <em>σ</em> = 0.95 μg/ mL.

Compute the probability of <em>X</em> within the range 0.05 to 4.95 μg/ mL as follows:

$P(0.05$

*Use a <em>z</em>-table for the probability.

Thus, the probability associated with the range lethal morphine blood levels is 0.9902.

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d) h(-1).

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2 years ago

Which statements are true regarding triangle LMN? Check all that apply.

dimaraw [331]

Answer:

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Step-by-step explanation:

Step 1: Pythagoras Theorem

Pythagoras theorem relates the three sides of the triangle in such a way that the sum of the square of base and perpendicular is equal to hypotenuse, such as:

$LM^{2} =LN^{2} +NM^{2}$

Step 2: Trigonometric Functions

Only for a right angle triangle following three trigonometric relations are valid

$sin (\theta) = \frac{opposite}{hypotenuse}$

$cos (\theta) = \frac{adjacent}{hypotenuse}$

$tan (\theta)=\frac{sin (\theta)}{cos (\theta)} = \frac{opposite}{adjacent}$

Step 3: Verifying all the possible answers

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we can calculate

$tan (\theta)= \frac{opposite}{adjacent}$

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therefore, NM = x (true)

B: As NM = x therefore it can not be equal to $x\sqrt{2\\}$ .

C: Using Pythagoras Theorem

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It can also be proved using trigonometric relation

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Therefore

$LM = x\sqrt{2}$

D and E:

Using same approach similar to part A

Since, LN = x and NM = x

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Therefore, $tan (45) = 1$ and not equal to $\frac{\sqrt{2} }{2}$

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Answer:

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Step-by-step explanation:

Here is the complete question

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6 0

2 years ago