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slega [8]
2 years ago
14

When you decrease the diameter of the stationary phase particles and make them more uniform, in HPLC, which term or terms of the

van Deemter Equation is or are minimized?
Chemistry
1 answer:
STALIN [3.7K]2 years ago
3 0

Answer:

C-term

Explanation:

A correlation between plate height and mobile phase velocity is known as the van Deemter equation.

H = A + \frac{B}{u}+ C*u

Where;

H is the plate height

A  is the eddy diffusion term

B is the longitudinal diffusion term

C is the resistance to mass transfer coefficient

u is the linear velocity

Here C-term describes the mass transfer of sample components between the stationary phase and the mobile phase during separation. One of the major factor affecting C-term is the particle size, changing the diameter equally changes the particle size.

The answer is C-term

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A toy car is placed at 0 on a number line. It moves 9 cm to the left, then 4 cm to the right, and then 6 cm to the left. What is
snow_lady [41]

Answer:

19

Explanation:

The total distance traveled by the toy cay would be 19 cm.

The total distance traveled should not be mistaken for total displacement. While displacement measures the distance and direction from the starting position of the toy car relative to its final position, the total distance traveled is calculated by adding all the movements of the toy car together. Hence;

Total distance traveled = 9 + 4 + 6 = 19 cm

7 0
2 years ago
Read 2 more answers
The distance between the atoms of H−I is 1.61Å. What is the distance in meters?
frosja888 [35]
<span>the answer is 
1A = 10^-10 m
so </span>1.61Å =  1.61  x 10^-10 m
he distance between the atoms of H−I is 1.61  x 10^-10 m
8 0
2 years ago
Oil is a fossil fuel used to run cars, heat up homes, and produce electricity. Oil can be removed from the bottom of the ocean t
Crazy boy [7]
The answers would be organisms in water, water, and air.
8 0
2 years ago
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Select the statement(s) that explain(s) the relationship between the arrangement of elements by size and first ionization energy
kow [346]

c. A full s subshell is able to shield a newly filled p subshell from the nucleus, making the first electron in a p subshell easy to remove.

Explanation:

From the given options, a full s-sublevel is able to shield a newly filled p-subshell from the nucleus thereby making the first electron in a p-subshell easy to remove is correct.

What is ionization energy?

Ionization energy is a measure of the readiness of an atom to lose an electron.

First ionization energy is the energy required to remove the most loosely held electron in the gas phase.

The size of an atom/element depends on the number of electrons it contains. The more the electrons, the larger its size.

  • The larger an atom becomes the lesser the ionization energy needed to remove the first electron from its outermost shell.

Electron - electron repulsion occurs when two electrons in the same sub-level repels one another.

Shielding effect is the ability of the inner electrons to protect the outer electrons from the pull of the nuclear charge.

In option C, a s-subshell has a greater shielding effect than the p,d and f sub-shell in that order.

A newly introduced electron in the p-sublevel will be loosely held and easier to remove.

Learn more:

First ionization energy brainly.com/question/2153804

#learnwithBrainly

8 0
2 years ago
Read 2 more answers
When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at
STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

1.22 * 10^{5} = - 8.314* 2400 * ln K

\\ 1.22 * 10^{5} = -19953.6 * ln K

ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022

So, the equilibrium constant is 0.0022.

4 0
2 years ago
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