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Papessa [141]
2 years ago
11

Select the statement(s) that explain(s) the relationship between the arrangement of elements by size and first ionization energy

.a. The two arrangements are the same because IE of elements increases from left to right and the radii of elements decreases from left to right.b. The first set of paired electrons in a p subshell experience a large amount of electron-electron repulsion, making the fourth electron in a p subshell easy to remove.c. A full s subshell is able to shield a newly filled p subshell from the nucleus, making the first electron in a p subshell easy to remove.d. The third unpaired electron in a p subshell causes a lot of electron-electron repulsion among the orbitals, making the third electron in a p subshell easy to remove.e. A p subshell with only one unpaired electron is extremely stable, making the fifth electron in a p subshell easy to remove.
Chemistry
2 answers:
kow [346]2 years ago
8 0

c. A full s subshell is able to shield a newly filled p subshell from the nucleus, making the first electron in a p subshell easy to remove.

Explanation:

From the given options, a full s-sublevel is able to shield a newly filled p-subshell from the nucleus thereby making the first electron in a p-subshell easy to remove is correct.

What is ionization energy?

Ionization energy is a measure of the readiness of an atom to lose an electron.

First ionization energy is the energy required to remove the most loosely held electron in the gas phase.

The size of an atom/element depends on the number of electrons it contains. The more the electrons, the larger its size.

  • The larger an atom becomes the lesser the ionization energy needed to remove the first electron from its outermost shell.

Electron - electron repulsion occurs when two electrons in the same sub-level repels one another.

Shielding effect is the ability of the inner electrons to protect the outer electrons from the pull of the nuclear charge.

In option C, a s-subshell has a greater shielding effect than the p,d and f sub-shell in that order.

A newly introduced electron in the p-sublevel will be loosely held and easier to remove.

Learn more:

First ionization energy brainly.com/question/2153804

#learnwithBrainly

quester [9]2 years ago
5 0

c. A full s subshell is ready to shield a newly filled p subshell from the nucleus, making the primary electron in an exceedingly p subshell easy to get rid of.

<h2>Further explanation </h2>

From the given options, a full s-sublevel {is able|is in an exceedingly position|is ready} to shield a newly filled p-subshell from the nucleus thereby making the primary electron in a p-subshell easy to get rid of is correct.

<h3>What is ionization energy? </h3>

Ionization energy may be a measure of the readiness of an atom to lose an electron.  First ionization energy is that the energy required to get rid of the foremost loosely held electron within the gas phase.  The size of an atom/element depends on the number of electrons it contains. The more the electrons, the larger its size.  The larger an atom becomes the lesser the ionization energy needed to get rid of the primary electron from its outermost shell.  Electron-electron repulsion occurs when two electrons within the same sub-level repel each other.  The shielding effect is the ability of the inner electrons to shield the outer electrons from the pull of the nuclear charge.

In option C, an s-subshell contains a greater shielding effect than the p,d, and f sub-shell therein order. A newly introduced electron within the p-sublevel is going to be loosely held and easier to get rid of.

Learn More

ionization energy  brainly.com/question/13811443

Electron-electron brainly.com/question/13811443

Details

Class: College

Subject: Chemistry

Keywords: ionization, energy, electron

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Compartments A and B are separated by a membrane that is permeable to K+ but not to Na+ or Cl-. At time zero, a solution of KCl
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Answer:

Incomplete question

Complete question:

8. Compartments A and B are separated by a membrane that is permeable to K+ but not to Na+ or Cl-. At time zero, a solution of KCl is poured into compartment A and an equally concentrated solution of NaCl is poured into compartment B. Which would be true once equilibrium is reached?

A. The concentration of Na+ in A will be higher than it was at time zero.

B. Diffusion of K+ from A to B will be greater than the diffusion of K+ from B to A.

C. There will be a potential difference across the membrane, with side B negative relative to side A.

D. The electrical and diffusion potentials for K+ will be equal in magnitude and opposite in direction.

E. The concentration of Cl- will be higher in B than it was at time zero.

Answer: D. The electrical and diffusion potentials for K+ will be equal in magnitude and opposite in direction.

Explanation:

Diffusion is the movement of molecules from region of higher concentration to lower concentration through a semipermeable membrane.

Since the k+ is the permeable membrane, the k+ ion in the KCl would move in equal magnitude and direction in the solution.

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2) Of the following, which has the shortest de Broglie wavelength? A) an airplane moving at a velocity of 300 mph B) a helium nu
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Answer:

B) a helium nucleus moving at a velocity of 1000 mph

Explanation:

According to the De Broglie relation

λ= h/mv

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As we can see from De Broglie's relation, the wavelength of matter waves depends on its mass and velocity. Hence, a very small mass moving at a very high velocity will have the greatest De Broglie wavelength.

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Answer:

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Explanation:

The reactivity of the carbonyl compound (ketone ) is affected by the steric effect. The steric effect is a hindrance that occurs in the structure or reactivity of a molecule, which is affected by the physical size and the proximity of the adjacent parts of the molecule.

Between 2-heptanone or 4-heptanone, 2-heptanone is more reactive than 4-heptanone. This is because 2-heptanone is less affected by the steric hindrance, unlike the 4-heptanone.

Similarly, the reactivity of the carbonyl compound (ketone) is also affected by the polarity on the carbon compound, which is associated with how electronegative the substituent attached is to the carbonyl compound. From the periodic table, the electronegativity of the Halogen family decreases down the group. Therefore chlorine is more electronegative than bromine.

As such, chloromethyl phenyl ketone is more reactive than bromomethyl phenyl ketone.

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2 years ago
Two species, A and B, are separated on a 2.00 m long column which has 5.000 x 103 plates when the flow rate is 15.0 mL/min. A sp
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Explanation:

The given data is as follows.

         t_{m} = 30.0 sec,     t_{r1} = 5 min = 5 \times 60 sec = 300 sec

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Formula for adjusted retention time is as follows.

      t'_{r} = t_{r} - t_{m}

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                 = 270 sec

   t'_{r2} = 720 sec - 30 sec

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Formula for relative retention (\alpha) is as follows.

          \alpha = \frac{t'_{r2}}{t'_{r1}}

                     = \frac{690 sec}{270 sec}

                     = 2.56

Thus, we can conclude that the relative retention is 2.56.

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