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stepladder [879]
2 years ago
9

Propane has the formula c3h8. if a sample of propane contains 0.20 moles of c, how many moles of h are present?

Chemistry
2 answers:
mixer [17]2 years ago
7 0

<u>Answer:</u> In the given sample, 0.533 moles of hydrogen will be present.

<u>Explanation:</u>

We are given a chemical compound having formula C_3H_8

We are provided with 0.20 moles of carbon atoms.

As, for every 3 moles of carbon atoms, 8 moles of hydrogen atoms are present.

So, for 0.20 moles of carbon atoms, \frac{8}{3}\times 0.20=0.533moles of hydrogen atoms will be present.

Hence, in the given sample, 0.533 moles of hydrogen will be present.

quester [9]2 years ago
5 0

Solving this problem only requires the knowledge of stoichiometry. We are given the compound propane C3H8. From the chemical formula, we can see that for every 3 moles of C, there are 8 moles of H. Therefore:

moles of H = 0.20 moles C * (8 moles H / 3 moles C)

<span>moles of H = 0.53 moles H</span>

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11111nata11111 [884]
When the amount of heat gained = the amount of heat loss

so, M*C*ΔTloses = M*C* ΔT gained

when here the water is gained heat as the Ti = 25°C and Tf= 28°C so it gains more heat.

∴( M * C * ΔT )W = (M*C*ΔT) Al

when Mw is the mass of water = 100 g 

and C the specific heat capacity of water = 4.18

and ΔT the change in temperature for water= 28-25 = 3 ° C

and ΔT the change in temperature for Al = 100-28= 72°C

and M Al is the mass of Al block

C is the specific heat capacity of the block = 0.9 

so by substitution:

100 g * 4.18*3 = M Al * 0.9*72

∴ the mass of Al block is = 100 g *4.18 / 0.9*72

                                          = 19.35 g 





4 0
2 years ago
The decomposition of nitramide, O 2 NNH 2 , O2NNH2, in water has the chemical equation and rate law O 2 NNH 2 ( aq ) ⟶ N 2 O ( g
valkas [14]

Answer:

Explanation:

The given overall reaction is as follows:

O 2 N N H ₂( a q ) k → N ₂O ( g ) + H ₂ O( l )

The reaction mechanism for this reaction is as follows:

O ₂ N N H ₂ ⇌ k 1 k − 1  O ₂N N H ⁻ + H ⁺ ( f a s t  e q u i l i b r i u m )

O ₂ N N H − k ₂→ N ₂ O + O H ⁻ ( s l ow )

H ⁺ + O H − k ₃→ H ₂ O ( f a s t )

The rate law of the reaction is given as follows:

k = [ O ₂ N N H ₂ ]  / [ H ⁺ ]

The rate law can be determined by the slow step of the mechanism.

r a t e = k ₂ [ O ₂ N N H ⁻ ] . . . ( 1 )

Since, from the equilibrium reaction

k e q = [ O ₂ N N H ⁻ ] [ H ⁺ ] /[ O ₂ N N H ₂ ] = k ₁ /k − 1

[ O ₂ N N H ⁻] = k ₁ /k − 1  × [ O ₂ N N H ₂ ] /[ H ⁺ ]. . . . ( 2 )

Substitituting the value of equation (2) in equation (1) we get.

r a t e = k ₂ k ₁/ k − 1  × [ O ₂ N N H ₂ ] /[ H ⁺ ]

Therefore, the overall rate constant is

k = k₂k₁/k-1

5 0
1 year ago
What is the percent composition by mass of nitrogen in the compound N2H4 (gram-formula mass = 32 g/mol)?
Alex

Answer:

\large \boxed{93\, \% }

Explanation:

1. Calculate the molar mass of N₂H₄

2N = 2 × 14 = 28

4H = 2 ×  1  = <u>  4</u>

           Tot. = 32

2. Calculate the mass percent of N

\text{\% of element} = \dfrac{\text{mass of element}}{\text{mass of compound}} \times 100 \, \% = \dfrac{\text{28}}{\text{32}} \times 100 \, \% =\mathbf{88 \, \%}\\\\\text{The percentage of N in N$_{2}$H$_{4}$ is $\large \boxed{\mathbf{88\, \% }}$}}

3 0
2 years ago
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How do models help scientists predict the polarity of molecules?
yuradex [85]

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Explanation:

8 0
1 year ago
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What is the [h3o + ] in a 0.050 m solution of ba(oh)2?
elena-14-01-66 [18.8K]
The H3O+ in a 0.050M  solution of Ba(OH)2  is calculated as below

write  the equation for the dissociation of Ba(OH)2

Ba(OH)2  =  Ba^2+  +2OH^-

calculate the OH-  concentration

by use of mole ratio between Ba(OH)2  to OH^- which is 1:2 the concentration of OH  =  0.050 x2  = 0.1 M

by  use of  the  formula ( H3O+)(OH-) =  1 x10 ^-14

by  making H3O+ the subject of the formula
H3O+ = 1 x10^-14/ OH-

substitute  for OH-

H3O+ =  (1 x10^-14 )/0.1

=  1  x10^-3  M
7 0
2 years ago
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