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Anestetic [448]
2 years ago
15

Cobalt-60 is a radioactive isotope used to treat cancers. A gamma ray emitted by this isotope has an energy of 1.33 MeV (million

electron volts; 1 eV = 1.602 x 10¹⁹ J). What is the frequency (in Hz) and the wavelength (in m) of this gamma ray?
Chemistry
1 answer:
Natalka [10]2 years ago
5 0

Answer:

E = 1.33 MeV = 2.13 x 10^{-13} J

v = wavelength = E / h = 2.13 x 10^{-13} / 6.626 x 10^{-34} = 3.2 x 10^{20} m

f = frequency = c / 3.2 x 10^{20} m = 3 x 10^{8} / 3.2 x 10^{20} = 9.375 x 10^{-13} Hz

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More here: https://www.hasd.org/faculty/AndrewSchweitzer/spectroscopy.pdf

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Compound X has the same molecular formula as butane but has a different boiling point and melting point. What can be concluded a
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Why does 4.03/0.0000035 = 1.2 x 106, instead of a different number of significant figures?
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Explanations:- As per the significant figures rule, In multiplication and division, we go with least number of sig figs.

4.03 has three sig figs where as 0.0000035 has two sig figs only, The zeros in this number are not sig figs as they are just holding the place values. As the least number of sig figs here is two, the answer needs to be reported with two sig figs only.

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2 years ago
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