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svetoff [14.1K]
2 years ago
10

Calculate the mass in grams of 0.800 mole of H2CO3. g

Chemistry
2 answers:
PilotLPTM [1.2K]2 years ago
6 0
MH₂CO₃: (1g×2) + 12g + (16g×3) = 62 g/mol

1 mol --- 62g
0,8 mol -- X
X = 0,8×62
X = 49,6g
Margarita [4]2 years ago
5 0

Explanation:

It is known that number of moles is equal to the mass divided by molar mass of a substance.

Mathematically,      No. of moles = \frac{mass}{\text{molar mass}}

Since it is given that number of moles is 0.80 mol and molar mass of H_{2}CO_{3} is 62.03 g/mol.

Therefore, we can conclude that mass of H_{2}CO_{3} is as follows.

                 No. of moles = \frac{mass}{\text{molar mass}}

                       0.80 mol = \frac{mass}{62.03 g/mol}

                             mass = 49.62 g

Thus, we can conclude that mass in grams of 0.800 mole of H_{2}CO_{3} is 49.62 g.

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Vesnalui [34]
 <span>2 KClO3(s) → 3 O2(g) + 2 KCl(s) 

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Answer:

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