Question

Calculate the mass in grams of 0.800 mole of H2CO3. g

Answer 1

MH₂CO₃: (1g×2) + 12g + (16g×3) = 62 g/mol

1 mol --- 62g
0,8 mol -- X
X = 0,8×62
X = 49,6g

Answer 2

Explanation:

It is known that number of moles is equal to the mass divided by molar mass of a substance.

Mathematically,      No. of moles = $\frac{mass}{\text{molar mass}}$

Since it is given that number of moles is 0.80 mol and molar mass of $H_{2}CO_{3}$ is 62.03 g/mol.

Therefore, we can conclude that mass of $H_{2}CO_{3}$ is as follows.

                 No. of moles = $\frac{mass}{\text{molar mass}}$

                       0.80 mol = $\frac{mass}{62.03 g/mol}$

                             mass = 49.62 g

Thus, we can conclude that mass in grams of 0.800 mole of $H_{2}CO_{3}$ is 49.62 g.