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2 years ago

Calculate the mass in grams of 0.800 mole of H2CO3. g

Chemistry

2 answers:

PilotLPTM [1.2K]2 years ago

6 0

MH₂CO₃: (1g×2) + 12g + (16g×3) = 62 g/mol

1 mol --- 62g
0,8 mol -- X
X = 0,8×62
X = 49,6g

Margarita [4]2 years ago

5 0

Explanation:

It is known that number of moles is equal to the mass divided by molar mass of a substance.

Mathematically, No. of moles = $\frac{mass}{\text{molar mass}}$

Since it is given that number of moles is 0.80 mol and molar mass of $H_{2}CO_{3}$ is 62.03 g/mol.

Therefore, we can conclude that mass of $H_{2}CO_{3}$ is as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.80 mol = $\frac{mass}{62.03 g/mol}$

mass = 49.62 g

Thus, we can conclude that mass in grams of 0.800 mole of $H_{2}CO_{3}$ is 49.62 g.

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