Explanation:
When we add chlorine to a substance or compound then this process is known as chlorination.
For example, a process of chlorination is as follows.
Initiation : 
where, Cl* is a free radical.
Propagation:
Termination:
Thus, we can conclude that out of the given options 
is not formed through a termination reaction in the chlorination of methane.
Answer:
20L
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 10L
Initial Temperature (T1) = stp = 273K
Final temperature (T2) = 546K
Final volume (V2) =..?
The new volume of the gas can be obtained by using the Charles' law equation as shown below:
V1/T1 = V2/T2
10/273 = V2/546
Cross multiply to express in linear form
273 x V2 = 10 x 546
Divide both side by 273
V2 = (10 x 546) / 273
V2 = 20L
Therefore, the new volume of the gas is 20L.
<span>Molar mass(C)= 12.0 g/mol
Molar mass (O2)=2*16.0=32.0 g/mol
Molar mass (CO2)=44.0 g/mol
18g C*1mol C/12 g C = 1.5 mol C
C + O2 → CO2
from reaction 1 mol 1 mol 1 mol
from problem 1.5 mol 1.5 mol 1.5 mol
1.5 mol O2*32 g O2/1 mol O2 = 48 g O2
In reality this reaction requires only 48 g O2 for 18 g carbon.
And from 18 g carbon you can get only
1.5 mol CO2*44 g CO2/1 mol CO2=66 g CO2
But these problem has 72g CO2. The best that we can think, it is a mix of CO2 and O2.
So to find all amount of O2 that was added for the reaction (probably people who wrote this problem wanted this)
we need (the mix of 72g - mass of carbon 18 g)= 54 g.
So the only answer that is possible is </span><span>2.) 54 g.</span>
