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liraira [26]
2 years ago
10

Which of the following species is not formed through a termination reaction in the chlorination of methane? Which of the followi

ng species is not formed through a termination reaction in the chlorination of methane? Cl2 CH3CH3 H2 CH3Cl
Chemistry
1 answer:
krek1111 [17]2 years ago
5 0

Explanation:

When we add chlorine to a substance or compound then this process is known as chlorination.

For example, a process of chlorination is as follows.

Initiation : Cl_{2} \overset{light}{\rightarrow} 2Cl*          

where, Cl* is a free radical.

Propagation:

    Cl* + CH_{4} \rightarrow HCl + *CH_{3}

    CH_{3} + Cl_{2} \rightarrow CH_{3}Cl + Cl*

Termination:

    2Cl* \rightarrow Cl_{2}

    Cl* + *CH_{3} \rightarrow CH_{3}Cl

    2*CH_{3} \rightarrow CH_{3}-CH_{3}

Thus, we can conclude that out of the given options H_{2} is not formed through a termination reaction in the chlorination of methane.

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Which of the following compounds would be most effective in lowering the melting point of ice on roads? a) CaCl2 b) NaCl C) K3PO
Mrac [35]
I'm not 100% sure on this, but I would go with C) NaCl. 
NaCl is a salt, and that is used to melt the ice on the roads. Hope this helps!
7 0
2 years ago
Write chemical equations and corresponding equilibrium expressions for each of the two ionization steps of carbonic acid. Part A
lesantik [10]

<u>Answer:</u> The chemical equations and equilibrium constant expression for each ionization steps is written below.

<u>Explanation:</u>

The chemical formula of carbonic acid is H_2CO_3. It is a diprotic weak acid which means that it will release two hydrogen ions when dissolved in water

The chemical equation for the first dissociation of carbonic acid follows:

               H_2CO_3(aq.)\rightleftharpoons H^+(aq.)+HCO_3^-(aq.)

The expression of first equilibrium constant equation follows:

Ka_1=\frac{[H^+][HCO_3^{-}]}{[H_2CO_3]}

The chemical equation for the second dissociation of carbonic acid follows:

               HCO_3^-(aq.)\rightarrow H^+(aq.)+CO_3^{2-}(aq.)

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][CO_3^{2-}]}{[HCO_3^-]}

Hence, the chemical equations and equilibrium constant expression for each ionization steps is written above.

6 0
2 years ago
An important reaction sequence in the industrial production of nitric acid is the following: N2(g) + 3H2(g) → 2NH3(g) 4NH3(g) +
frutty [35]

Answer:

The answer to your question is 50 moles of O₂

Explanation:

Balanced Chemical reactions

1.-                 N₂(g)  +  3H₂ (g)   ⇒   2NH₃ (g)

2.-                4NH₃ (g) + 5O₂(g)  ⇒  4NO (g)  +  6H₂O (l)

moles of N₂(g) = 20 moles

moles of O₂(g) = ?

Process

1.- Calculate the moles of NH₃

                     1 mol of N₂ ------------- 2 moles of NH₃

                   20 moles of N₂ ---------  x

                     x = (20 x 2) / 1

                     x = 40 moles of NH₃

2.- Calculate the moles of O₂

                4 moles of NH₃ -------------- 5 O₂

               40 moles of NH₃ ------------  x

                    x = (40 x 5) / 4

                    x = 200 / 4

                    x = 50 moles of O₂

3 0
2 years ago
Carbon dioxide readily absorbs radiation with an energy of 4.67 x 10-20 J. What is the wavelength and frequency of this radiatio
Tanya [424]

Answer:

ν = 7.04 × 10¹³ s⁻¹

λ = 426 nm

It falls in the visible range

Explanation:

The relation between the energy of the radiation and its frequency is given by Planck-Einstein equation:

E = h × ν

where,

E is the energy

h is the Planck constant (6.63 × 10⁻³⁴ J.s)

ν is the frequency

Then, we can find frequency,

\nu = \frac{E}{h}=  \frac{4.67 \times 10^{-20}J  }{6.63 \times 10^{-34}J.s} = 7.04 \times 10^{13} s^{-1}

Frequency and wavelength are related through the following equation:

c = λ × ν

where,

c is the speed of light (3.00 × 10⁸ m/s)

λ is the wavelength

\lambda = \frac{c}{\nu } =\frac{3.00 \times 10^{8} m/s }{7.04 \times 10^{13} s^{-1} } =4.26 \times 10^{-6}m.\frac{10^{9}nm }{1m} = 426 nm

A 426 nm wavelength falls in the visible range (≈380-740 nm)

7 0
2 years ago
Identify the type of solid from the description. Select from the following choices: metallic solid, network solid, molecular sol
scZoUnD [109]

First of all, there are five types of solid materials:  

Metallic solids which are solids composed of metal atoms that are held together by metallic bonds.

Network solid is a chemical compound in which the atoms are bonded by covalent bonds in a continuous network extending throughout the material.

Molecular solid is a solid consisting of discrete molecules.  

Ionic solid is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding.  

Amorphous solid is non-crystalline solid that lacks the long-range order that is characteristic of a crystal.

Now, after the defined all the types of solid materials in the equation lets to solve it.  

A. the answer is the network solids, because covalent bonds are relatively strong, covalent are typically characterized by hardness, strength, and high melting points.

B. the answer is the metallic solids, due to that heat conduction occurs when a substance is heated and the particles will gain more energy vibrating more. These molecules then bump into nearby particles and transfer some of their energy to them and in metals this process have a higher probability than in the case of other solids due to the nature of the chemical bonds. It also has a range of hardness due to the strength of metallic bonds which varies dramatically.

C. the answer is the ionic solid; due to positive and negative ions which are  bonded to form a crystalline solid held together by charge attractions.

4 0
2 years ago
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