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denpristay [2]
2 years ago
7

The atomic number of nitrogen is 7. nitrogen-15 has a greater mass number than nitrogen-14 because the atomic nucleus of nitroge

n-15 contains _____. 8 neutrons 15 protons 7 neutrons 8 protons
Chemistry
2 answers:
schepotkina [342]2 years ago
7 0
8 neutrons (7 protons)
Paha777 [63]2 years ago
5 0

Answer: Option (a) is the correct answer.

Explanation:

Atomic number means the sum of total number of protons acquired by an atom.

So, when atomic number of nitrogen is 7 then it means there are 7 protons present.

Whereas atomic mass means the sum of total number of protons and neutrons present in an atom.

Therefore, nitrogen-15 is an isotope of nitrogen that will always have 7 protons when it is neutral in nature. Hence, in nitrogen-15 the number of protons and neutrons are calculated as follows.

                   Atomic mass = no. of protons + no. of neutrons

                             15 = 7 + no. of neutrons

                    no. of neutrons = 15 - 7

                                               = 8

Thus, we can conclude that the atomic nucleus of nitrogen-15 contains 8 neutrons.

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siniylev [52]

we are given

a swimming pool contains 2,850 kiloliters (kL) of water

2,850 kiloliters (kL)=2850000L

we know that

1gal=3.785L

3.785L=1gal

Firstly , we will find for 1L

1L=\frac{1}{3.785}gal

now, we can multiply both sides by 2850000

2850000*1L=2850000*\frac{1}{3.785}gal

2850000L=2850000*\frac{1}{3.785}gal

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a swimming pool contains 752972.25892gal of water...........Answer


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2 years ago
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ddd [48]

Answer :

The enthalpy of reaction is, -187.6 kJ/mol

The total heat will be, -2251 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

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(c) Now we have to calculate the total heat.

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or,

q=\Delta H\times n

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\Delta H = enthalpy change = -187.6 kJ/mol

q = heat = ?

n = number of moles of coal = \frac{1.00\times 1000g}{12.00g/mol}=83.33mol

Now put all the given values in the above formula, we get:

q=(-187.6kJ/mol)\times (83.33mol)=-2.251kJ

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