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dangina [55]
2 years ago
10

A chemical engineer must report the average volume of a certain pollutant produced by the plants under her supervision. Here are

the data she has been given by each plant: plant volume of pollutant Macon 0.519 LAllegheny 44.67 LDoheny 0.826 LWhat average volume should the chemical engineer report? Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
AfilCa [17]2 years ago
5 0

Answer:

The chemical engineer should report average volume of 15.34 L.

Explanation:

Volume of Macon = 0.519 L

Volume of Allegheny = 44.67 L

Volume of Doheny = 0.826 L

Average of the volume of the pollutants:

\frac{0.519 L+44.67 L+ 0.826L}{3}=\frac{46.015 L}{3}=15.33833 L

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

Here the 44.67  has two significant digit after decimal point.So the answer will be reported as in with 2 significant figures after decimal point.

15.33833 L\approx 15.34 L

The chemical engineer should report average volume of 15.34 L.

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Industrial production of nitric acid, which is used in many products including fertilizers and explosives, approaches 10 billion
mylen [45]

Answer: 9.361\times 10^{4} kJ

Explanation:

The balanced chemical equation :

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)  \Delta H^0_{rxn}=-902.0kJ

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{7.056\times 10^3g}{17g/mol}=415.1moles

According to stoichiometry:

4 moles of NH_3 produces = 902.0 kJ of energy

415.1 moles of NH_3 produces =\frac{902.0}{4}\times 415.1=9.361\times 10^{4} kJ of energy

Thus the change in enthalpy is 9.361\times 10^{4} kJ

5 0
2 years ago
Calcium-45 has a half-life of 162.7 days. If four half-lives have elapsed, how much time has passed?
vovikov84 [41]
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7 0
1 year ago
Read 2 more answers
What mass (g) of barium iodide is contained in 188 ml of a barium iodide solution that has an iodide ion concentration of 0.532m
Katarina [22]

Answer:

What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?

A) 19.6

B) 39.1

C) 19,600

D) 39,100

E) 276

The correct answer to the question is

B) 39.1  grams

Explanation:

To solve the question

The molarity ratio is given by

188 ml of 0.532 M solution of iodide.

Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles

To find the mass, we note that the Number of moles = \frac{Mass}{Molar Mass} from which we have

Mass = Number of moles × molar mass

Where the molar mass of Barium Iodide = 391.136 g/mol

= 0.100016 moles ×391.136 g/mol = 39.12 g

8 0
1 year ago
A small cube of iron and a large flat sheet of iron contain the same volume. Which one will completely rust first? Explain why.
allochka39001 [22]
Flat as more oxygen and water can react over it think of it like this would a cube rust faster than a sheet
6 0
1 year ago
Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equil
Illusion [34]

Answer:

Part A

K = (K₂)²

K = (K₃)⁻²

Part B

K = √(Ka/Kb)

Explanation:

Part A

The parent reaction is

2Al(s) + 3Br₂(l) ⇌ 2AlBr₃(s)

The equilibrium constant is given as

K = [AlBr₃]²/[Al]²[Br₂]³

2) Al(s) + (3/2) Br₂(l) ⇌ AlBr₃(s)

K₂ = [AlBr₃]/[Al][Br₂]¹•⁵

It is evident that

K = (K₂)²

3) AlBr₃(s) ⇌ Al(s) + 3/2 Br₂(l)

K₃ = [Al][Br₂]¹•⁵/[AlBr₃]

K = (K₃)⁻²

Part B

Parent reaction

S(s) + O₂(g) ⇌ SO₂(g)

K = [SO₂]/[S][O₂]

a) 2S(s) + 3O₂(g) ⇌ 2SO₃(g)

Ka = [SO₃]²/[S]²[O₂]³

[SO₃]² = Ka × [S]²[O₂]³

b) 2SO₂(g) + O₂(g) ⇌ 2 SO₃(g)

Kb = [SO₃]²/[SO₂]²[O₂]

[SO₃]² = Kb × [SO₂]²[O₂]

[SO₃]² = [SO₃]²

Hence,

Ka × [S]²[O₂]³ = Kb × [SO₂]²[O₂]

(Ka/Kb) = [SO₂]²[O₂]/[S]²[O₂]³

(Ka/Kb) = [SO₂]²/[S]²[O₂]²

(Ka/Kb) = {[SO₂]/[S][O₂]}²

Recall

K = [SO₂]/[S][O₂]

Hence,

(Ka/Kb) = K²

K = √(Ka/Kb)

Hope this Helps!!!

6 0
1 year ago
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