The formula for chromium (III) phosphate trihydrate is CrPO4- 3H20. This compound if in the anhydrous state, exists as a green crystal whereas a hydrated form violet crystal. The formula for cobalt(II) phosphate octahydrate is Co3(PO4)2•8H2O.
Answer:
d. One single bond and two double bonds.
Explanation:
The octate rule is a chemical rule in which the atoms prefer to have eight electrons in the valence shell. Where a single bond provide two electrons and a double bond provide 4 electrons. Thus:
a. Two double bonds
. Two double bonds provide 8 electrons. Octate rule <em>is not </em>violated
b. Three single bonds and one pair of electrons
. Three single bonds provide 6 electrons and one pair of electrons provide two electrons. Thus, you have eight electrons and octate rule <em>is not</em> violated
c. Two single bonds and one double bond
. Two single bonds provide four electrons and one double bond 4. Thus, you have eight electrons and octate rule <em>is not </em>violated.
d. One single bond and two double bonds. One single bond provides two electrons and two double bonds 8. Thus, you have 10 electrons and <em>octate rule is violated.</em>
e. Four single bonds. Four single bonds provide 8 electrons. Octate rule<em> is not </em>violated.
I hope it helps!
Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions. So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3.
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole. So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
Answer: It is 5450 mL
Explanation: There are 1000 mL in every L and then there is an extra 450 so just add that at the end
