A grocery store has 75 dozen packages of hotdogs In stock. If there are 10 hot dogs in each package, how many moles of hot dogs
is this?
2 answers:
Answer:
Explanation:
First we will calculate the amount of hot dog units we have:
-75 dozen packages (a dozen is 12 )=75x12=900 packages
-each package has 10 hot dogs=900x10=9000 hot dog units
We know a mole of something is units of that something. And that will be our conversion factor for this excercise. We will convert now from 9000 units of hot dogs to moles of hot dogs like this:
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Answer : The temperature of the gas is, 245.9 K
Explanation :
To calculate the temperature of gas we are using ideal gas equation:
where,
P = pressure of gas = 2770.96 torr = 3.646 atm
Conversion used : (1 atm = 760 torr)
V = volume of gas = 88.84 L
T = temperature of gas = ?
R = gas constant = 0.0821 L.atm/mole.K
w = mass of gas = 609.64 g
M = molar mass of gas = 38 g/mole
Now put all the given values in the ideal gas equation, we get:
Therefore, the temperature of the gas is, 245.9 K
Answer : Both solutions contain molecules.
Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain molecules.
Avogadro's Number is =
which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.
Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.
Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.
Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.
We can calculate the number of molecules for each;
Number of molecules = ;
∴ Number of molecules = which will be =
Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.