Answer: 0.0007 moles of 
is released when temperature is raised.
Explanation:
To calculate the number of moles, we use the ideal gas equation, which is:
where,
P = pressure of the gas = 1.01 bar
V = Volume of the gas = 1L
R = Gas constant = 
- Number of moles when T = 20° C
Temperature of the gas = 20° C = (273 + 20)K = 293K
Putting values in above equation, we get:
- Number of moles when T = 25° C
Temperature of the gas = 25° C = (273 + 25)K = 298K
Putting values in above equation, we get:
- Number of moles released =
Hence, 0.0007 moles of is released when temperature is raised from 20° C to 25° C
Basically team B would win since it is exerting a force of 900N unlike team A ( you can tell by doing 4900N minus 4000N ). It is very unbalanced.
The compound contains Carbon, Hydroxide and Oxide
1 mole of carbon iv oxide contains 44 g, out of which 12 g are carbon.
Therefore, 1.6004 g of CO2 will contain;
1.6004 ×12/44 = 0.4365 g of carbon
1 mole of water contains 18 g of which 2 g is hydrogen,
Therefore, 0.6551 g of H2O will hace ;
0.6551 × 2/18 = 0.0728 g of hydrogen.
The total mass of the compound is 0.8009 g,
Thus the mass of oxygen = 0.8009 -(0.4365 +0.0728)
= 0.2916 g
To get the empirical formula we first get the number of moles of each element;\
Carbon = 0.4365/12= 0.036375 moles
Hydrogen = 0.0728/1 = 0.0728 moles
Oxygen = 0.2916/16 = 0.018225 moles
Then, to get the smallest ratio we divide each with the smallest value;
Carbon : Hydrogen : Oxygen
= (0.036375/0.018225) : (0.0728/0.018225) : ( 0.018225/0.018225)
= 1.996 : 3.995 : 1
≈ 2 : 4 : 1
Therefore, the empirical formula is C2H4O
The grams of the sugar in 125 g of the drink is calculated as below
%M/m) = mass of the solute (sugar)/ mass of the solvent(drink) x100
let the mass of the solute(sugar) be represented by y
convert % into fraction by dividing by 100 = 10.5/100
10.5/100 = y/125
by cross multiplication
100y =1312.5
divide both side by 100
y=13.125 grams
