F = ma = (kg)(m/s2) = kg ´ m/s2 N
hope this helps :D
Answer:
Mole fraction = 0,0166
Explanation:
Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.
The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:
91,7g fructose × (1mol / 180,16g) = <em>0,509 moles of fructose</em>
545g water × (1mol / 18,02g) = <em>30,24 moles of water</em>
Thus, mole fraction of fructose is:

<em>Mole fraction = 0,0166</em>
I hope it helps!
The answer would be B. Brimone. I had the same question before, but let me know if it is not right. Cause certain schools have the same questions but different answers for them.
Answer:

Explanation:
Assume you are using 1 L of water.
Then you are washing 4 L of salty oil.
1. Calculate the mass of the salty oil
Assume the oil has a density of 0.86 g/mL.

2. Calculate the mass of salt in the salty oil

3. Calculate the mass of salt in the spent water

4. Mass of salt remaining in washed oil
Mass = 172 g - 150 g = 22 g
5. Concentration of salt in washed oil

10 g of glue with 13 g of water ,
Mass ratio of the material can be calculated as:
8 g of sodium borate suspended in 11 g of water, mass ratio can be calculated as:
