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katovenus [111]
2 years ago
14

When 3-bromo-2,4-dimethylpentane is treated with sodium hydroxide, only one alkene is formed?

Chemistry
1 answer:
jonny [76]2 years ago
6 0
<span>Answer: 3 bromo 2,4 dimethylpentane undergoes sn1 mechanism and hence forms a racemic mixture containing both r and s forms of the compound. in the first step that is the slow step a 2 degree carbocation is formed with positve charge at carbon 3 then it undergoes rearrangement to a 3 degree carbocation at carbon 2 from either side. as the carbocation contains 6 electrons in the outermost shell only it is sp2 hybridized and hence planar in structure, now the second step proceeds and the attack of -OH group takes place, as the -OH(hydroxyl) group can attack from either side, (top or bottom), hence a racemic mixture of 2,4 dimethyl pentan-2-ol is formed.</span>
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2 years ago
A solution is prepared by dissolving 91.7 g fructose in 545 g of water. Determine the mole fraction of fructose if the final vol
oee [108]

Answer:

Mole fraction = 0,0166

Explanation:

Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.

The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:

91,7g fructose × (1mol / 180,16g) = <em>0,509 moles of fructose</em>

545g water × (1mol / 18,02g) = <em>30,24 moles of water</em>

Thus, mole fraction of fructose is:

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<em>Mole fraction = 0,0166</em>

I hope it helps!

5 0
2 years ago
an element x has two naturally occurring isotopes: X-79 (abundance+50.69%, mass +78.918amu) and X-81 (abundance+49.31% mass+80.9
Lana71 [14]
The answer would be B. Brimone. I had the same question before, but let me know if it is not right. Cause certain schools have the same questions but different answers for them.
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2 years ago
Salt in crude oil must be removed before the oil undergoes processing in a refinery. The
irina1246 [14]

Answer:

\large \boxed{0.64 \, \%}

Explanation:

Assume you are using 1 L of water.

Then you are washing 4 L of salty oil.

1. Calculate the mass of the salty oil

Assume the oil has a density of 0.86 g/mL.

\text{Mass of oil} = \text{4000 mL} \times \dfrac{\text{0.86 g}}{\text{1 mL}} = \text{3440 g}

2. Calculate the mass of salt in the salty oil

\text{Mass of salt} = \text{3440 g} \times \dfrac{\text{5 g salt}}{\text{100 g oil}} = \text{172 g salt}

3. Calculate the mass of salt in the spent water

\text{Mass of salt} = \text{1000 g water} \times \dfrac{\text{15 g salt}}{\text{100 g water}} = \text{150 g salt}

4. Mass of salt remaining in washed oil

Mass = 172 g - 150 g = 22 g  

5. Concentration of salt in washed oil

\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}

3 0
2 years ago
If you perform the experiment described in investigation #15 by mixing 10 g of glue with 13 g of water and 8 g of sodium borate
Phantasy [73]

10 g of glue with 13 g of water ,

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\frac{ 8 g}{ 8 g + 11 g }  

\frac{8 g}{19 g }

3 0
2 years ago
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