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Alenkinab [10]
1 year ago
12

You are designing an office building. In order to reduce noise from high-frequency sounds between offices above and below each o

ther, would you choose carpet on concrete or wood floors? Explain your answer.
Chemistry
2 answers:
Monica [59]1 year ago
8 0

Answer:

concrete has more mass and it will block more noise than than the wood plus the wood is thiner the thicker the substance is the better u won't hear noise

Explanation:

miskamm [114]1 year ago
7 0
Carpet for sure. Have you ever heard how loud a dog walking on wood compared to carpet is.
You might be interested in
Zinc is to be electroplated onto both sides of an iron sheet that is 20 cm2 as a galvanized sacrificial anode. It is desired to
Alexandra [31]

Answer:

The time required for the coating is 105 s

Explanation:

Zinc undergoes reduction reaction and absorbs two (2) electron ions.

The expression for the mass change at electrode (m_{ch}) is given as :

\frac{m_{ch}}{M} ZF = It

where;

M = molar mass

Z = ions charge at electrodes

F = Faraday's constant

I = current

A = area

t = time

also; (m_{ch}) = (Ad) \rho ; replacing that into above equation; we have:

\frac{(Ad) \rho}{M} ZF = It  ---- equation (1)

where;

A = area

d = thickness

\rho = density

From the above equation (1); The time required for coating can be calculated as;

[ \frac{20 cm^2 *0.0025 cm*7.13g/cm^3}{65.38g/mol}*2 \frac{moles\ of \ electrons}{mole \ of \ Zn} * 9.65*10^4 \frac{C}{mole \ of \ electrons }  ] = (20 A) t

t = \frac{2100}{20}

= 105 s

8 0
2 years ago
At 4.00 L, an expandable vessel contains 0.864 mol of oxygen gas. How many liters of oxygen gas must be added at constant temper
fgiga [73]

Answer:

We have to add 2.30 L of oxygen gas

Explanation:

Step 1: Data given

Initial volume = 4.00 L

Number of moles oxygen gas= 0.864 moles

Temperature = constant

Number of moles of oxygen gas increased to 1.36 moles

Step 2: Calculate new volume

V1/n1 = V2/n2

⇒V1 = the initial volume of the vessel = 4.00 L

⇒n1 = the initial number of moles oxygen gas = 0.864 moles

⇒V2 = the nex volume of the vessel

⇒n2 = the increased number of moles oxygen gas = 1.36 moles

4.00L / 0.864 moles = V2 / 1.36 moles

V2 = 6.30 L

The new volume is 6.30 L

Step 3: Calculate the amount of oxygen gas we have to add

6.30 - 4.00 = 2.30 L

We have to add 2.30 L of oxygen gas

4 0
2 years ago
Elemental analysis of the unknown gas from part a revealed that it is 30.45% n and 69.55% o. what is the molecular formula for t
Gnesinka [82]

Assuming we have 100 g of sample

30.45/MW of N 14g = 2.175

69.55/MW of O 16g = 4.34

4.34/2.185 = 2

for every 1 mole of N we have 2 moles of O

so the empirical formula would be NO2

without having the molecular weight of the entire molecule the molecular formula can not be determined with the information in your question

6 0
2 years ago
PLZ HELP ASAP PLATO!!! BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!!
katen-ka-za [31]

Explanation:

a. 0.0093

Number of significant figures = 2

All zero’s preceding the first integers are never significant

b. 120.9

Number of significant figures = 4

All zero’s between integers are always significant.

c. 1,000

Number of significant figures = 1

All zeroes used solely for spacing the decimal point are not significant.

d. 1.008

Number of significant figures = 4

All zero’s between integers are always significant.

All zero’s after the decimal point are always significant.

e. 670

Number of significant figures = 2

All zeroes used solely for spacing the decimal point are not significant.

f. 0.184

Number of significant figures = 3

All zero’s after the decimal point are always significant.

g. 1.30

Number of significant figures = 3

All zero’s after the decimal point are always significant.

3 0
2 years ago
Alkanes are hydrocarbons containing only single bonds. Acyclic alkanes have carbon atoms arranged in chains, whereas cycloalkane
sashaice [31]

Answer:

156 Hydrogen atoms

Explanation:

<u>Any acyclic alkane has a molecular formula that can be expressed as</u>:

CₙH₂ₙ₊₂

Where <em>n</em> is any integer and the number of carbon atoms. For example, Propane has 3 carbon atoms, this means it would have [2*3+2] 8 hydrogen atoms, resulting with a formula of C₃H₈.

An acyclic alkane with 77 carbon atoms would thus have:

2*77 + 2 = 156 hydrogen atoms

4 0
2 years ago
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