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kiruha [24]
2 years ago
11

How many chloride ions are in 0.486 moles of chloride ions?​

Chemistry
1 answer:
svetlana [45]2 years ago
6 0

Answer:

Since in a chloride ion, we have an additional electron

you might think that it will affect the mass but the mass of an electron is almost negligible so we will ignore that

Amount of ions in 1 mol = 6.022 * 10^23

Amount of ions in 0.486 moles = 0.486 * (6.022*10^23)

Amunt of ions in 0.486 moles = 2.9 * 10^23 ions

Hence, option 1 is correct

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Diatomic hydrogen gas and diatomic nitrogen gas react spontaneously to form a gaseous product. Give the balanced chemical equati
alex41 [277]

Answer : NH_{3}

Explanation : When diatomic hydrogen gas and diatomic nitrogen gas reacts spontaneously it forms ammonia gas as the product.

we will have the following reactions; As all the reactants and products are in the gaseous state the subscript (g) is given to the molecules.

H_{2}_{(g)} + N_{2}_{(g)} ----> NH_{3}_{(g)}

But this is not a balanced equation, as on the right side of reactants we have 2 hydrogen atoms and 2 nitrogen atoms which gives the product which has one nitrogen and three hydrogen in the compound state.

So, balancing the equation, we get,

3H_{2}_{(g)} + N_{2}_{(g)} ----> 2NH_{3}_{(g)}

We multiplied 2 with the diatomic hydrogen molecule which resulted in production of 2 moles of ammonia as the product.

So, the complete balanced equation is;

3H_{2}_{(g)} + N_{2}_{(g)} ----> 2NH_{3}_{(g)}

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2 years ago
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As an atom's nucleus gets larger the electric charges repelling the protons get larger. To compensate for this greater electric
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Before landing, the brakes and the tires of an airliner have a temperature of 15.0∘C. Upon landing, the 90.7 kg carbon fiber bra
Goryan [66]

Answer:

0.921 J/g degrees C

Explanation:

Recall that the First Law of Thermodynamics demands that the total internal energy of an isolated system must remain constant. Any amount of energy lost by the brakes must be gained by the tires (in the form of heat in this situation).  Therefore, heat given off by the brakes = −heat taken in by tires, or:

−qbrakes=qtires

The equation used to calculate the quantity of heat energy exchanged in this process is:

−qbrakes=−cbrakes mbrakes ΔTbrakes=ctires mtires ΔTtires=qtires

First we must convert the mass of the tires and the brakes from  kg to  g.

massbrakes=90.7 kg×1,000. g1 kg=9.07×104 g

masstires=123 kg×1,000. g1 kg=1.23×105 g

Next, substitute in known values and rearrange to solve for ctires. Note that the final temperature for both the tires and the brakes is 172∘C, the initial temperature of the brakes is 312∘C and the initial temperature of the tires is 15∘C.

−(1.400Jg∘C)(9.07×104 g)(172∘C−312∘C)=(ctires)(1.23×105 g)(172∘C−15∘C)

ctires=−(1.400 Jg∘C)(9.07×104 g)(−140∘C)(1.23×105 g)(157∘C)=17,777,200 J19311000 g∘C=0.9206Jg∘C

The answer should have three significant figures, so round to 0.921Jg∘C.

6 0
2 years ago
Experiments have shown that the equilibrium constant Kp for the reaction NO(g) + NO2(g) ⇌ N2O3(g) is 0.03. A chamber with a cons
zepelin [54]

Answer:

The reaction will shift to the right

Explanation:

In the reaction:

NO(g) + NO₂(g) ⇌ N₂O₃(g)

Kp of reaction is:

kP = \frac{P_{N_2O_3} }{P_{NO}P_{NO_{2}}} = 0.03

<em>Where P represents the pressures in equilibrium</em>

Replacing in the kP formula the initial pressures:

\frac{50MPa}{200MPa*250MPa} = 0.001

As the <em>Reaction quotient (Q) </em>is less than kP, <em>the reaction will shift to the right </em>producing more N₂O₃ until Q = kP.

7 0
2 years ago
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