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miv72 [106K]
2 years ago
5

An atom of 120In has a mass of 119.907890 amu. Calculate the mass defect (deficit) in amu/atom. Use the masses: mass of 1H atom

Chemistry
1 answer:
diamong [38]2 years ago
6 0

Answer:

a

Explanation:

answer is a on edg

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If an electronic balance reports an object weighing 35.9920g what will be displayed when
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Answer:

2.0000 g

Explanation:

It will show the number out to the 4th decimal place.  Exactly 2 g will be displayed as 2.0000 g.

8 0
2 years ago
Consider the elements in the periodic table. The stair-step line between the pink squares and the yellow squares separates the _
Maru [420]
I believe the correct answer from the choices listed above is option B. The stair-step line between the pink squares and the yellow squares separates the metals <span>from the nonmetals. Hope this answers the question. Have a nice day.</span>
4 0
2 years ago
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A 32.5 g piece of aluminum (which has a specific heat capacity of 0.921 J/g°C) is heated to 82.4°C and dropped into a calorimete
N76 [4]

Answer:

The mass of water = 219.1 grams

Explanation:

Step 1: Data given

Mass of aluminium = 32.5 grams

specific heat capacity aluminium = 0.921 J/g°C

Temperature = 82.4 °C

Temperature of water = 22.3 °C

The final temperature = 24.2 °C

Step 2: Calculate the mass of water

Heat lost = heat gained

Qlost = -Qgained

Qaluminium = -Qwater

Q = m*c*ΔT

m(aluminium)*c(aluminium)*ΔT(aluminium) = -m(water)*c(water)*ΔT(water)

⇒with m(aluminium) = the mass of aluminium = 32.5 grams

⇒with c(aluminium) = the specific heat of aluminium = 0.921 J/g°C

⇒with ΔT(aluminium) = the change of temperature of aluminium = 24.2 °C - 82.4 °C =  -58.2 °C

⇒with m(water) = the mass of water = TO BE DETERMINED

⇒with c(water) = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = 24.2 °C - 22.3 °C = 1.9 °C

32.5 * 0.921 * -58.2 = -m * 4.184 * 1.9

-1742.1 = -7.95m

m = 219.1 grams

The mass of water = 219.1 grams

8 0
2 years ago
List the number of each type of atom on the left side of the equation 2C10H22(l)+31O2(g)→20CO2(g)+22H2O(g)
ValentinkaMS [17]

Answer: There are 20 carbons atoms, 62 oxygen atoms and 44 carbon atoms on the left side of the equation.

Explanation:

In the given chemical reaction:

2C_{10}H_{22}(l)+31O_2(g)\rightarrow 20CO_2(g)+22H_2O(g)

Reactants side = Left side

Number of atoms =

Coefficient × Number of atoms of an element in a unit molecular formula

Number of carbon atoms = 2 × 10 = 20

Number of oxygen atoms = 31 × 2 = 62

Number of hydrogen atoms =  2 × 22 = 44

8 0
2 years ago
How many moles of O2 would be required to generate 13.0 mol of NO₂ in the reaction below assuming the reaction has only 73.3% yi
Airida [17]

Answer:

Mmmmmmmmmmmmmmm

Explanation:

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1 year ago
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