The elements X and Y combine in different ratios to form four different types of compounds: XY, XY2, XY3, and XY4. Consider that
there is enough of each compound to contain 2 g of X. In XY the mass of X is 2 g and the mass of Y is 4 g.
Arrange the following ratios in order of their increasing value. Rank from highest to lowest ratio. To rank items as equivalent, overlap them.
1. The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY.
2. The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY.
3. The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY.
Arrange the following ratios in order of their increasing value. Rank from highest to lowest ratio. To rank items as equivalent, overlap them.
1. The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY.
2. The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY.
3. The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY.
1 answer:
Answer:
Ratios in order of increasing value ; The ratio of the mass ratio of Y to X in XY2 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY3 to the mass ratio of Y to X in XY, The ratio of the mass ratio of Y to X in XY4 to the mass ratio of Y to X in XY
1) Mass ratio = 3
2) Mass ratio = 2
3) Mass ratio = 4
Explanation:
The detailed and step by step calculation is shown in the attachment.
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Answer:
The volume of the container is 59.112 L
Explanation:
Given that,
Number of moles of Oxygen, n = 3
Temperature of the gas, T = 300 K
Pressure of the gas, P = 1.25 atm
We need to find the volume of the container. For a gas, we know that,
PV = nRT
V is volume
R is gas constant, R = 0.0821 atm-L/mol-K
So,
So, the volume of the container is 59.112 L