Eva buys a package of food, and the nutrition label says that

Green light has a frequency of about 6.00×1014s−1. What is the energy of a photon of green light?

Sindrei [870]

3.98 x 10⁻¹⁹ Joule

<h3>Further explanation</h3>

<u>Given:</u>

The green light has a frequency of about 6.00 x 10¹⁴ s⁻¹.

<u>Question:</u>

The energy of a photon of green light (in joules).

<u>The Process:</u>

The energy of a photon is given by $\boxed{\boxed{ \ E = hf \ }}$

E = energy in joules
h = Planck's constant 6.63 x 10⁻³⁴ Js
f = frequency of light in Hz (sometimes the symbol f is written as v)

Let us find out the energy of the green light emitted per photon.

$\boxed{ \ E = (6.63 \times 10^{-34})(6.00 \times 10^{14}) \ }$

Thus, we get a result of $\boxed{\boxed{ \ E = 3.98 \times 10^{-19} \ J \ }}$

- - - - - - - - - -

Notes

When an electron moves between energy levels it must emit or absorb energy.
The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons.
A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.

<h3>Learn more</h3>

The energy of the orange light emitted per photon brainly.com/question/2485282#
Determine the density of our sun at the end of its lifetime brainly.com/question/5189537
Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays brainly.com/question/5416146

Keywords: green light, frequency, the energy, a photon, Planck's constant, electrons, emitted, wavelength, joules

7 0

2 years ago

What is the mass, in grams, of 0.450 moles of Sb?

murzikaleks [220]

Answer:

54.9 g

Explanation:

0.450 mol x 122g/mol

7 0

2 years ago

Read 2 more answers

Write a balanced equation for the transmutation that occurs when a scandium-48 nucleus undergoes beta decay.

Tju [1.3M]

Answer:

A scandium-48 nucleus undergoes beta-minus decay to produce a titanium-48 nucleus.

$\rm ^{48}_{21}Sc \to ^{48}_{22}Ti + ^{\phantom{1}\,0}_{-1}e^{-} + \bar{\mathnormal{v}}_e$ .

Explanation:

There are two types of beta decay modes: beta-minus and beta-plus.

In both decay modes, the mass number of the nucleus stays the same.

However, in a beta-minus decay, the atomic number of the nucleus increases by one. In a beta-plus decay, the atomic number decreases by one.

Each beta-minus decay releases one electron and one electron antineutrino. Each beta-plus decay releases one positron and one electron neutrino.

Look up the atomic number and relative atomic mass for the element scandium.

The atomic number of $\rm Sc$ is $21$ .
The relative atomic mass of $\rm Sc$ is approximately $45.0$ .

This question did not specify whether the decay here is beta-plus or a beta-minus. However, the relative atomic mass of this element can give a rough estimate of the mode of decay.

Each element (e.g, $\rm Sc$ ) can have multiple isotopes. These isotopes differ in mass. The relative atomic mass of an element is an average across all isotopes of this element. This mass is weighted based on the relative abundance of the isotopes. Its value should be closest to the most stable (and hence the most abundant) isotope.

The mass number of scandium-48 is significantly larger than the relative atomic mass of this element. In other words, this isotope contains more neutrons than isotopes that are more stable. There's a tendency for that neutron to convert to a proton- by beta-minus decay, for example.

The atomic number of the nucleus will increase by 1. $21 + 1 = 22$ . That corresponds to titanium. The mass number stays the same at $48$ . Hence the daughter nucleus would be titanium-48. Note that two other particles: one electron and one electron $\rm e^{-}$ and one antineutrino $\bar{v}_{\text{e}}$ (note the bar.) The neutrino helps balance the lepton number of this reaction.

6 0

1 year ago

The decomposition of AB given here in this balanced equation 2AB (g)⟶ A2 (g) + B2 (g), has rate constants of 8.58 x 10-9 L/mol s

denis-greek [22]

Answer:

3.24 × 10^5 J/mol

Explanation:

The activation energy of this reaction can be calculated using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

Where; Ea = the activation energy (J/mol)

R = the ideal gas constant = 8.3145 J/Kmol

T1 and T2 = absolute temperatures (K)

k1 and k2 = the reaction rate constants at respective temperature

First, we need to convert the temperatures in °C to K

T(K) = T(°C) + 273.15

T1 = 325°C + 273.15

T1 = 598.15K

T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now find Ea

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

8 0

1 year ago

Be sure to answer all parts. ethyl butanoate, ch3ch2ch2co2ch2ch3, is one of the many organic compounds isolated from mangoes. wh

GrogVix [38]

Ethyl Butanoate when treated with a base looses a proton which is more acidic in nature. In this case ethyl butanoate acts as a lowery bronsted acid. It donated the more acidic proton to lowery bronsted base.

Among the protons attached to different carbon atoms the hydrogen atoms next to carbonyl functional group (labelled as red in attached picture) are more acidic in nature and are readily donated on treatment with strong base. These hydrogen atoms are also called alpha hydrogen name after their position.

Acidity of Alpha Hydrogens:

The driving force behind the acidity of alpha hydrogens is the formation of enolates. The enolate formed is resonance stabilized. This stability is the main reason for the said acidity. The pKa value of said protons is approximately 20-25. Hence, the enolate formed is infact the conjugate base and can act as neucleophile.

4 0

2 years ago