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sesenic [268]
2 years ago
12

Jocelyn has 400 pounds of chemical A that she must react with 200 pounds of chemical B to create chemical C for use in an indust

rial manufacturing process. How many pounds of chemical C will Jocelyn have after the reaction is complete?
Chemistry
2 answers:
denis-greek [22]2 years ago
6 0

Answer:

600

Explanation:

adoni [48]2 years ago
4 0
This chemical reaction should follow the Law of Conservation of Mass where mass cannot be created nor destroyed. That is, what goes in a system should be equal with what goes out the system. For this problem, the mass of C that is produced assuming there are no by-products should be 600 pounds.
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Which two scenarios illustrate the relationship between pressure and volume as described by Boyle’s law?
Kruka [31]

Answer:

2) The volume of an underwater bubble increases as it rises and the pressure decreases

hope it was useful for you

stay at home stay safe

5 0
2 years ago
At 4.00 L, an expandable vessel contains 0.864 mol of oxygen gas. How many liters of oxygen gas must be added at constant temper
fgiga [73]

Answer:

We have to add 2.30 L of oxygen gas

Explanation:

Step 1: Data given

Initial volume = 4.00 L

Number of moles oxygen gas= 0.864 moles

Temperature = constant

Number of moles of oxygen gas increased to 1.36 moles

Step 2: Calculate new volume

V1/n1 = V2/n2

⇒V1 = the initial volume of the vessel = 4.00 L

⇒n1 = the initial number of moles oxygen gas = 0.864 moles

⇒V2 = the nex volume of the vessel

⇒n2 = the increased number of moles oxygen gas = 1.36 moles

4.00L / 0.864 moles = V2 / 1.36 moles

V2 = 6.30 L

The new volume is 6.30 L

Step 3: Calculate the amount of oxygen gas we have to add

6.30 - 4.00 = 2.30 L

We have to add 2.30 L of oxygen gas

4 0
2 years ago
A mixture containing KClO3,K2CO3,KHCO3, and KCl was heated, producing CO2,O2, and H2O gases according to the following equations
Nikitich [7]

<u>Answer:</u>

<u>For 1:</u> The mass of KClO_3 in the original mixture is 10.46 g

<u>For 2:</u> The mass of KHCO_3 in the original mixture is 21.11 g

<u>Explanation:</u>

We are given:

Mass of water = 1.90 g

Mass of carbon dioxide = 13.64 g

Mass of oxygen = 4.10 g

  • <u>For 1:</u>

The given chemical reaction for decomposition of KClO_3 follows:

2KClO_3\rightarrow 2KCl+3O_2

By Stoichiometry of the reaction:

(3\times 32)=96g of oxygen is produced when (2\times 122.5)=245g of potassium chlorate is decomposed.

So, 4.10 g of oxygen will be produced when = \frac{245}{96}\times 4.10=10.46g of potassium chlorate is decomposed.

Amount of KClO_3 in the mixture = 10.46 g

  • <u>For 2:</u>

The given chemical reaction for decomposition of KHCO_3 follows:

2KHCO_3\rightarrow K_2O+H_2O+2CO_2

By Stoichiometry of the reaction:

18 g of water is produced when (2\times 100)=200g of potassium bicarbonate is decomposed.

So, 1.90 g of water will be produced when = \frac{200}{18}\times 1.90=21.11g of potassium bicarbonate is decomposed.

Amount of KHCO_3 in the mixture = 21.11 g

4 0
2 years ago
Suppose a species of snake is living in a certain area. Some of the snakes in the population are black and some are orange. Over
nikdorinn [45]

The theory of biological evolution known as Darwin's theory of evolution or Darwinism given by Charles Darwin an English naturalist. According to the theory, all the species of organisms develop and originate via the natural selection of minor, inherited changes, which enhances the tendency of an individual to survive, compete, and develop the tendency to give rise to new ones.  

Thus, according to Darwin's theory of evolution in the given case of black and orange snakes, the black snakes will survive and reproduce, therefore, passing their traits to their offspring, while few orange snakes will remain in the population.  

6 0
2 years ago
Read 2 more answers
To determine the ammonia concentration in a sample of lake water, three samples are prepared. In sample A, 10.0 mL of lake water
Masteriza [31]

Answer:Sample Absorbance (625 nm)  

A 0.536  

B 0.783  

C 0.045  

Therefore, I will use these data to solve your question. If you have other absorbances values, just follow my steps and plug in different numbers.

First, we see 1 mole of NH3 gives 1 mole product.

In B moles of NH3 = moles of NH3 in A + (5.5 x10^-4 x2.5/1000) = 1.375 x10^6 + mA

( mA = moles of NH3 in A) vol of B = 25 = vol of A

now A = el C = eC ( since l = 1cm)

Because, n net absorbance due to complex blank absorbance must be removed.

Here A(A) = 0.536 - 0.045 = 0.491 , A(B) = 0.783 - 0.045 = 0.738  

(you can plug in different numbers in this step)

A2/A1 = C2/C1 , A(B)/A(A) = (1.375x10^-6 +mA)/(mA) = 0.738/0.491

So, mA = 2.733 x 10^-6 = moles of NH3 in A (Lake water)

Hence [NH3] water ( 2.733 x10^-6 ) x 1000/25 = 1.093 x 10^-4 M

Lake water vol = 10 ml out of 25,

Concentration of ammonia in lake water = 2.733 x10^-6 x 1000/10 = 2.733 x 10^-4 M

Then, A = 0.491 = e x 1 x 1.093 x10^-4

e = 4492 M-1cm-1

Explanation:

4 0
2 years ago
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