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vodomira [7]
2 years ago
8

The first five ionization energies of an element are as follows (in kJ/mol): 577.9, 1820, 2750, 11600, 14800. Which of the follo

wing elements is most likely to have these ionization energy values?
a. Na
b. Mg
c. AI
d. Si
e. P
Chemistry
1 answer:
Ne4ueva [31]2 years ago
4 0

Answer:option d==> Si.

Explanation:

The energy required to remove electron from a gaseous atom or ion is what is called an ionization energy. As we remove electrons continually in a gaseous atom or ion, the ionization energy increases which are know as the first ionization energy, the second ionization energy, third ionization energy and so on.

Looking at the electronic configuration of Silicon, Si; Ne 3s2 3p2. We can can see that the first four ionization energies are from the removal of the 3p2 and 3s2 electrons and the fifth ionization energy, which is the highest ionization energy of 14800 kJ/mol is the the electron removed from the core shell.

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<h3>Answer:</h3>

             Formal Charge on Nitrogen is "Zero".

<h3>Explanation:</h3>

Formal Charge on an atom in molecules is calculated using following formula;

Formal Charge  =  [# of Valence e⁻s] - [e⁻s in lone pairs + 1/2 # of Bonding e⁻s]

As shown in attached picture of Hydroxylamine, Nitrogen atom is containing two electrons in one lone pair of electrons and six electrons in three single bonds with two hydrogen and one oxygen atom respectively.

Hence,

                                  Formal Charge  =  [5] - [2 + 6/2]

                                  Formal Charge  =  [5] - [2 + 3]

                                  Formal Charge  =  5 - 5

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Hence, the formal charge on nitrogen atom in hydroxylamine is zero.

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1 year ago
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Answer:

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Explicación:

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