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ozzi
2 years ago
7

What is the [H3O+]in a solution of pOH 0.253

Chemistry
1 answer:
Luda [366]2 years ago
4 0
Carbonated water would be what you are looking for :v)
You might be interested in
Imagine that a new polyatomic anion called "platoate" is invented. What would an acid of "platoate" be named?
o-na [289]
<h3>Answer:</h3>

                   Platoic Acid

<h3>Explanation:</h3>

                        While naming Carboxylic Acids we know that when the Carboxylic Acid looses proton it is converted into corresponding conjugate base called as Carboxylate.

Examples:

                        HCOOH           →           HCOO⁻  +  H⁺

                     Formic acid                     Formate Ion

                    H₃CCOOH           →           H₃CCOO⁻  +  H⁺

                     Acetic acid                       Acetate Ion

                    H₅C₂COOH           →           H₅C₂COO⁻  +  H⁺

                 Propanoic acid                       Propanoate Ion

Therefore, if the conjugate base is Platoate then the corresponding acid will be Platoic Acid means we will replace the -ate by -ic acid <em>i.e.</em>

                   RCOO⁻  +  H⁺        →            RCOOH

                   Platoate Ion                         Platoic Acid

8 0
2 years ago
Read 2 more answers
The average density of a carbon-fiber-epoxy composite is 1.615 g/cm3. the density of the epoxy resin is 1.21 g/cm3 and that of t
ra1l [238]
The composite material is composed of carbon fiber and epoxy resins. Now, density is an intensive unit. So, to approach this problem, let's assume there is 1 gram of composite material. Thus, mass carbon + mass epoxy = 1 g.

Volume of composite material = 1 g / 1.615 g/cm³ = 0.619 cm³
Volume of carbon fibers = x g / 1.74 g/cm³ 
Volume of epoxy resin = (1 - x) g / 1.21 g/cm³ 

a.) V of composite = V of carbon fibers + V of epoxy resin
0.619 = x/1.74 + (1-x)/1.21
Solve for x,
x = 0.824 g carbon fibers
1-x = 0.176 g epoxy resins

Vol % of carbon fibers = [(0.824/1.74) ÷ 0.619]*100 =<em> 76.5%</em>

b.) Weight % of epoxy = 0.176 g epoxy/1 g composite * 100 = <em>17.6%</em>
     Weight % of carbon fibers = 0.824 g carbon/1 g composite * 100 = <em>82.4%</em>
4 0
2 years ago
How many grams of calcium cyanide (Ca(CN)2) are contained in 0.79 mol of calcium cyanide?
Allushta [10]
I dont know but do you know da wae brudda?


3 0
2 years ago
Consider a culture medium on which only gram-positive organisms such as Staphylococcus aureus colonies can grow due to an elevat
Olin [163]
<h2>Selective & Differential Medium</h2>

Explanation:

  • Selective media allow specific types of organisms to develop, and inhibit the development of different living beings. The selectivity is cultivated in a few ways.For model, living beings that can use a given sugar are handily screened by making that sugar the main carbon source in the medium. On the other hand,selective hindrance of certain sorts of microorganisms can be accomplished by adding dyes, anti-infection agents, salts or explicit inhibitors which influence the digestion or enzyme systems of the living beings
  • Differential media are utilized to separate firmly related life forms or groups of living beings. owing to the pre of specific colors or synthetic compounds in the media, the creatures will deliver trademark changes or development designs that are utilized for ID or separation. An assortment of particular and differential media are utilized in clinical, demonstrative and water contamination research facilities, and in food and dairy laboratories
  • Selective media because elevated NaCI level is designed to help grow selective bacteria.differential media because the fermented sugar gives off a yellow halo which allows for differentiate between bacteria

4 0
2 years ago
The equilibrium constant for the reaction sr(s) + mg2+(aq) ⇌ sr2+(aq) + mg(s) is 2.69 × 1012 at 25°c. calculate e o for a cell m
Mariulka [41]
Sr(s)+Mg²+(aq)→Sr²+(aq)+Mg(s)
Number of e-'s transfered are, n=2. Equilibrium constant,
K=2.69×10∧12
ΔG=-2.303RT logK
R=gasconstant=8.314J/mol-k
T= temperature in K= 25 oC=25+273=298K
The value we get ΔG = -70922.3J. But ΔG = -nFE
n= number of e-'s transfered in the reaction =2
F= farady = 96500C
E=potential of the cell is what?
∴E = ΔG.nF
=-(-70922.3)/2×96500)
=0.367v.
8 0
2 years ago
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