During this phase Change heat energy is being absorbed by the molecules, and as a result the molecules possess a greater ability to move around and possess higher kinetic energy because of this. The molecules also possess a higher potential energy.
Answer:
HOMO of 1,3-butadiene and LUMO of ethylene
HOMO of ethylene LUMO of 1,3-butadiene
Explanation:
1,3 - butadiene underogoes cycloaddition reaction with ethylene to give cyclohexene.
According to Frontier molecular orbital theory HOMO of 1,3 butadiene and LUMO of ethylene and HOMO of ethylene and LUMO of ethylene underoges (4 + 2) in thermal or photochemical condition.
Answer:
a. Yes, it is flammable.
b. It can cause hazard and carcinogenic effect.
Explanation:
A. Yes, the vapor in the vessel is flammable because it is an organic solvent with a very low boiling point. For this reason, less energy can vaporize it. Therfore, a little high temperature or energy causes it to be very reactive and flammable.
B. - Being flammable makes it hazardous, that is, it is capable of being ignited and can burn easily, which makes it really dangerous.
- It results in carcinogenic effect on the body. Substances that cause carcinogenic effect are capable of increasing the risk of cancer. They might contain compounds that can initiate tumor.
When the temperature is high, the risk of explosion increases. Due to the fact that at higher temperature, the kinetic energy of the atoms which result in an increase in the volume and finally blasting of the vessel.
Answer:
The number of moles of potassium hydroxide, KOH required to make 4 moles of K₂SO₄ is 8 moles of KOH
Explanation:
2KOH + H₂SO₄ → K₂SO₄ + 2H₂O
From the above reaction, we have 2 moles of KOH combining with 1 mole of H₂SO₄ to produce 1 mole of K₂SO₄ and 2 moles of H₂O.
Therefore the number of moles of potassium hydroxide that will be needed to make 4 moles of K₂SO₄ is;
8KOH + 4H₂SO₄ → 4K₂SO₄ + 8H₂O
8 moles of KOH is required to make 4 moles of K₂SO₄.
Total in pot=28 L
400 mL in each bowl
16 bowls filled
1000mL=1L
16 bowls(400mL/1 bowl)=6400mL
6400mL(1L/1000mL)=6.4L
28L-6.4L=21.6 L
