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Savatey [412]
2 years ago
6

In a voltaic cell made of a Ag strip and an Al strip immersed in 1.0 M aqueous AgNO_3 and Al(NO_3)_3 solutions, respectively, wi

th all other cell components in place, the Al strip is oxidized, thereby losing mass as the voltaic cell operates. What is the primary reason the Al strip loses mass
Chemistry
1 answer:
Tema [17]2 years ago
7 0

Answer:

When the operation of the voltaic cell, which is formed of an aluminum and silver strip takes place, the atom of aluminum loses three of its electrons and the Al3+ formed moves within the solution. The Al3+ ion gets dissolved within the solution and the electrons lost in the process moves through the wire and get acquired by the ions of silver, which then get reduced to solid Ag resulting in the mass gain of silver strip.

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What is the name of Br6F10 ?
astraxan [27]

Answer:

idfk

Explanation:

3 0
1 year ago
During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.
Brrunno [24]

Answer: 19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.

0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2

3 0
1 year ago
Which of the following statements best describes the properties of aluminum-28?
Contact [7]

d. When aluminum-28 undergoes beta decay, silicon-28 is produced.

Explanation:

When the nuclei of aluminium-28 decays, it produces silicon- 28:

    Aluminium    ²⁸₁₃Al

    Silicon 28      ²⁸₁₄Si

    beta particle     ⁰₋₁\beta

       

           ²⁸₁₃Al        →          ²⁸₁₄Si      +        ⁰₋₁\beta

This way, the mass and atomic number are conserved.

Conservation of mass number:

                28 = 28 + 0,  28 = 28

                 13 = 14 -1 ,       13 = 13

Learn more:

Balancing nuclear equations brainly.com/question/10094982

#learnwithBrainly

       

5 0
2 years ago
When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t
lisov135 [29]

Answer:

1.59mol/L

Explanation:

Data obtained from the question include:

Mass of MgCl2 = 151g

Volume of water(solvent) = 1L

Now, let us calculate the number of mole of MgCl2. This is illustrated below:

Molarity Mass of MgCl2 = 24 + (2x35.5) = 24 + 71 = 95g/mol

Mass of MgCl2 = 151g

Number of mole of MgCl2 =?

Number of mole = Mass /Molar Mass

Number of mole of MgCl2 = 151/95

Number of mole of MgCl2 = 1.59mole

Now we can calculate the molarity of MgCl2 as follow:

Mole = 1.59mole

Volume = 1L

Molarity =?

Molarity = mole /Volume

Molarity = 1.59/1

Molarity = 1.59mol/L

8 0
1 year ago
KClKCl has a lattice energy of −701 kJ/mol.−701 kJ/mol. Consider a generic salt, ABAB , where A2+A2+ has the same radius as K+,K
elena-14-01-66 [18.8K]

Explanation:

It is given that lattice energy is -701 kJ/mol.

Whereas it is known that realtion between lattice energy and radius is as follows.

               Lattice energy \propto \frac{Z_{+}Z_{-}}{r}

where,          Z_{+} = +2,    and Z_{-} = -2

Therefore, lattice energy of AB = 4 \times \text{lattice energy of KCl}

                                                    = 4 \times -701 kJ/mol

                                                    = -2804 kJ/mol

Thus, we can conclude that lattice energy of the salt ABAB is -2804 kJ/mol.

6 0
1 year ago
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