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Margarita [4]
2 years ago
5

A gas sample enclosed in a rigid metal container at room temperature (20.0∘C) has an absolute pressure p1. The container is imme

rsed in hot water until it warms to 40.0∘C. What is the new absolute pressure p2? Express your answer in terms of p1.
Chemistry
1 answer:
Vlad [161]2 years ago
5 0

Answer : The new absolute pressure is, 1.068\times P_1

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_2}{P_1}=\frac{T_2}{T_1}

where,

P_1 = initial pressure of gas

P_2 = final pressure of gas

T_1 = initial temperature of gas = 20.0^oC=273+20.0=293.0K

T_2 = final temperature of gas = 40.0^oC=273+40.0=313.0K

Now put all the given values in the above equation, we get:

\frac{P_2}{P_1}=\frac{313.0K}{293.0K}

\frac{P_2}{P_1}=1.068

P_2=1.068\times P_1

Therefore, the new absolute pressure is, 1.068\times P_1

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Umnica [9.8K]
<h2>The number of moles of formaldehyde can be produced by reacting 4.0 moles of methanol with 4.0 moles of oxygen gas is <u>8 moles</u></h2>

<u> explanation</u>

write   a balanced chemical reaction

that is 2 CH3OH (l) +  O2 (g) →  2HCOH (l)+ 2H2O (l)

from the reaction above  2 moles of CH3OH reacted with 1 moles of O2 to form 2 moles of HCOH and two moles of H2O

This imply that O2 is the limiting reagent ,therefore by use of mole ratio between  O2 : HCOH which is 1 :2 the moles of HCOH= 2 x4 =  8 moles

5 0
2 years ago
Read 2 more answers
Calculate the amount of energy in kilojoules needed to change 459 g of water ice at −10 ∘C to steam at 125 ∘C. The following con
egoroff_w [7]

Answer: 1.41\times 10^3kJ

Explanation:-

The conversions involved in this process are :

(1):H_2O(s)(-10^0C)\rightarrow H_2O(s)(0^0C)\\\\(2):H_2O(s)(0^0C)\rightarrow H_2O(l)(0^0C)\\\\(3):H_2O(l)(0^0C)\rightarrow H_2O(l)(100^0C)\\\\(4):H_2O(l)(100^0C)\rightarrow H_2O(g)(100^0C)\\\\(5):H_2O(g)(100^0C)\rightarrow H_2O(g)(125^0C)

Now we have to calculate the enthalpy change:

\Delta H=[n\times c_{ice}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[n\times c_{water}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[n\times c_{steam}\times (T_{final}-T_{initial})]

where,

\Delta H = enthalpy change = ?

m = mass of water = 459 g

c_{s} = specific heat of ice = 36.57J/mol^0C

c_{l} = specific heat of water =  75.40J/mol^0C

c_{g} = specific heat of steam = 36.04J/gmol^0C

n = number of moles of water = \frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{459g}{18g/mole}=25.5mole

\Delta H_{fusion} = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

\Delta H_{vap} = enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get:

\Delta H=[25.5mole\times 36.57J/mol^0C\times (0-(-10))^0C]+25.5mole\times 6010J/mole+[25.5mole\times 75.40J/mol^0C\times (100-0)^0C]+25.5mole\times 40670J/mole+[25.5mole\times 36.04J/gmol^0C\times (125-100)^0c]

\Delta H=1414910.85J=1.41\times 10^3kJ    

(1kJ = 1000 J)

Therefore, the enthalpy change is 1.41\times 10^3kJ

4 0
2 years ago
Which of the following rock formations likely existed before the development of a stack?
Nataly_w [17]

Answer: A) sea arch

Explanation:

A natural arch or sea arch can be defined as a natural bridge which forms with an opening underneath.  A natural arch or sea arch is formed when the stacks are subjected to erosion. A stack can be defined as the geological form that is formed by the water wave erosion due to vertical column. The sea arches form inland cliffs, fins and other forms.

7 0
2 years ago
The vapor pressure of liquid iodomethane, CH3I, is 100. mm Hg at 266 K. A 0.453 g sample of liquid CH3I is placed in a closed, e
Elanso [62]

Answer:

a. Yes

b. 143.5 mmHg

Explanation:

The vapor pressure is the pressure of the vapor that is in equilibrium with the liquid. At a constant temperature, some molecules of the liquid will vaporize, and then will do pressure at the surface of the liquid.

If the pressure at the container is higher then the vapor pressure, the liquid will evaporate.

a. Let's calculate the pressure at the container by the ideal gas law:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (62,364 mmHg.mL/mol.K), and T is the temperature.

The molar mass of CH₃I is 142 g/mol

n = mass/ molar mass

n = 0.453/142

n = 0.0032 mol

P*370 = 0.0032*62,364*266

370P = 53,084.24

P = 143.5 mmHg

So, all the liquid will evaporate.

b. Because all liquid evaporates, when the equilibrium is reached, the pressure is the gas pressure: 143.5 mmHg.

3 0
2 years ago
List the bonding pairs H and I; S and O; K and Br; Si and Cl, H and F; Se and S; C and H in order of increasing covalent charact
stellarik [79]

Answer:

1. (S,O) < (Se,S) < (C,H) = (H,I) = (H,F) < (Si,Cl) < (K,Br)

Explanation:

The covalent character always increases down the group, this is because ionic character decreases down the group and also electronegativity.

In the same way, Covalent character always decreases across a period because electronegativity increases across a period.

The higher the electronegativity values between the two atoms, the more ionic it will be.

5 0
2 years ago
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