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Lisa [10]
2 years ago
12

The reaction H+ + HCO3â€"" <--> H2CO3 is a part of the respiration process. It takes place at _____ . A. the lungs and tis

sue cells B. neither the lungs nor tissue cells C. the tissue cells D. the lungs
Chemistry
2 answers:
Anettt [7]2 years ago
8 0

Answer:the correct option here is C

Explanation:

Ok, the correct equation for the reaction is given below;

H^+ + HCO3^- <------------> H2CO3.

This reaction do occur in the blood in the tissues.

THE REACTION STEPS:

(1). Carbondioxide, CO2 goes into the blood stream and combines with water to form the carbonic acid, H2CO3.

CO2 + H2O <------------------> H2CO3.

Although, this reaction reaction is slow, it is catalyzed by a protein enzyme, carbonic anhydrase in the red blood cells.

(2). The carbonic acid,H2CO3 dissociates into H^+ and HCO3^-

H^+ + HCO3^- <--------------> H2CO3.

The HCO3^- acts as buffer in the blood.

The Carbonic acid is then converted into Carbondioxide back for expulsion in the lungs.

Paladinen [302]2 years ago
6 0

Answer:

The tissue cells

Explanation:

I think you mean this

H^{+}+HCO^{3} ^{-}  H_{2}CO_{3}

It all starts from Carbondioxide. This Carbondioxide is dissolved in the blood and taken by red blood cell and converted into carbonic acid. It then dissociates to form a bicarbonate ion HCO^{3} ^{-} and a hydrogen ion H^{+}

This <--> means that the whole process is reversible. It is a buffer system to maintain the pH in the blood and duodenum. And also to support proper metabolic function.

You might be interested in
1) Aluminum sulphate can be made by the following reaction: 2AlCl3(aq) + 3H2SO4(aq) Al2(SO4)3(aq) + 6 HCl(aq) It is quite solubl
kolezko [41]

Answer:

88.9%

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2AlCl3(aq) + 3H2SO4(aq) —> Al2(SO4)3(aq) + 6HCl(aq)

Step 2:

Determination of the masses of AlCl3 and H2SO4 that reacted and the mass of Al2(SO4)3 produced from the balanced equation.

Molar mass of AlCl3 = 27 + (35.5x3) = 133.5g/mol

Mass of AlCl3 from the balanced equation = 2 x 133.5 = 267g

Molar mass of H2SO4 = (2x1) + 32 + (16x4) = 98g/mol

Mass of H2SO4 from the balanced equation = 3 x 98 = 294g

Molar mass of Al2(SO4)3 = (27x2) + 3[32 + (16x4)]

= 54 + 3[32 + 64]

= 54 + 3[96] = 342g/mol

Mass of Al2(SO4)3 from the balanced equation = 1 x 342 = 342g

Summary:

From the balanced equation above,

267g of AlCl3 reacted with 294g of H2SO4 to produce 342g of Al2(SO4)3.

Step 3:

Determination of the limiting reactant. This is illustrated below:

From the balanced equation above,

267g of AlCl3 reacted with 294g of H2SO4.

Therefore, 25g of AlCl3 will react with = (25 x 294)/267 = 27.53g of H2SO4.

From the calculations made above, we see that only 27.53g out 30g of H2SO4 given were needed to react completely with 25g of AlCl3.

Therefore, AlCl3 is the limiting reactant and H2SO4 is the excess.

Step 4:

Determination of the theoretical yield of Al2(SO4)3.

In this case we shall be using the limiting reactant because it will produce the maximum yield of Al2(SO4)3 since all of it is used up in the reaction.

The limiting reactant is AlCl3 and the theoretical yield of Al2(SO4)3 can be obtained as follow:

From the balanced equation above,

267g of AlCl3 reacted to produce 342g of Al2(SO4)3.

Therefore, 25g of AlCl3 will react to produce = (25 x 342) /267 = 32.02g of Al2(SO4)3.

Therefore, the theoretical yield of Al2(SO4)3 is 32.02g

Step 5:

Determination of the percentage yield of Al2(SO4)3.

This can be obtained as follow:

Actual yield of Al2(SO4)3 = 28.46g

Theoretical yield of Al2(SO4)3 = 32.02g

Percentage yield of Al2(SO4)3 =..?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 28.46/32.02 x 100

Percentage yield = 88.9%

Therefore, the percentage yield of Al2(SO4)3 is 88.9%

3 0
2 years ago
Which of the following statements is true about the following reaction?
MAVERICK [17]

The correct reaction equation is:

3NaHCO_{3} (aq) + C_{6}H_{8}O_{7} (aq) \rightarrow 3CO_{2} (g) + 3H_{2}O (l) + Na_{3}C_{6}H_{5}O_{7} (aq)

Answer:

b) 1 mole of water is produced for every mole of carbon dioxide produced.

Explanation: <u>CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.</u>

a) <u>22.4 L of CO_{2} gas</u> is produced only when <u>\frac{22.4}{3} L of  C_{6}H_{8}O_{7}</u> is reacted with 22.4 L of NaHCO_{3}. So it is wrong.

b) Since in the chemical equation the stoichiometric coefficient of CO_{2}  and H_{2}O are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. <u>Therefore it is correct option.</u>

c)  6.02\times 10^{23} molecules is equal 1 mole of Na_{3}C_{6}H_{5}O_{7} if produced then 3 moles of NaHCO_{3} is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of H_{2}O (<em>Molecular Weight of water is 18 g</em>) is produced when 3 moles of NaHCO_{3} is used but in this option only one mole of NaHCO_{3} is given. So it is wrong.

8 0
2 years ago
Read 2 more answers
A balloon inflated with three breaths of air has a volume of 1.7 L. At the same temperature and pressure, what is the volume of
Karolina [17]

Ans: The final volume of the balloon is 4.5 L

<u>Given:</u>

Volume of balloon inflated with 3 breaths = 1.7 L

<u>To determine:</u>

Volume of balloon after a total of 3+5 = 8 breaths

<u>Explanation:</u>

Volume of the balloon per breath = 1.7 L * 1 breath/3 breaths = 0.567 L

Final volume of balloon after 8 breaths = 0.567 L * 8 breath/1 breath

= 4.536 L

7 0
2 years ago
Write the products of photosystem i and photosystem ii
Margaret [11]
<span>ATP,O2 and NADPH are the </span>products<span>. H2O,NADP,ADP and Pi are the reactants. acts as an electron carrier between the cytochrome b6f and </span>photosystem 1 (PS1) complexes in the photosynthetic electron-transfer chain.

Photosystem II<span> (or water-plastoquinone oxidoreductase) is the first protein complex in the light-dependent reactions of oxygenic photosynthesis. It is located in the thylakoid membrane of plants, algae, and cyanobacteria.</span>
3 0
2 years ago
Read 2 more answers
How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?
raketka [301]
Hydrogen reacts with oxygen to form water based on the following equation:
2H2 + O2 ..............> 2H2O
This means that 4 grams of hydrogen are required to react with 32 grams of oxygen to release 36 grams of water.
We need to calculate how munch oxygen is needed to react with 4.8 grams of hydrogen. We can do this using cross multiplication as follows:
amount of oxygen = (4.8x32) / 4 = 38.4 grams

This means that we have no limiting reagent here and both reactants will completely react.
We know that 4 grams of hydrogen are required to produce 36 grams of water. Therefore:
amount of water produced from 4.8 grams of hydrogen = (4.8 x 36) /4 = 43.2 grams
3 0
2 years ago
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