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jasenka [17]
2 years ago
15

Convert 1.3902 hectoliters to centiliters.

Chemistry
2 answers:
hram777 [196]2 years ago
8 0
<span>The answer is 13,902 centiliters.

</span>
Minchanka [31]2 years ago
7 0

Explanation:

It is known that mathematically, 1 hectoliter is equal to 10,000 centiliters. As we are given 1.3902 hectoliters so, we will convert it into centiliters as follows.

                    1 hectoliter = 10,0000 centiliter

Centiliters present in 1.3902 hectoliters will be calculated as follows.

         1.3902 hectoliter \times \frac{10,000 centilieters}{1 hectoliter}

            = \frac{13902}{10,000} \times 10,000 centiliters

            = 13902 centiliters

Thus, we can conclude that there are 13902 centiliters in 1.3902 hectoliters.

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In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?
Vinvika [58]

Total number of atoms in the sample is the sum of number of atoms of all the elements present in the sample.

Number of gold, Au atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms     (given)

From the formula of compound that is KAu(CN)_2 it is clear that the number of potassium and gold are same whereas those of carbon and nitrogen are 2 times of them.

So, the number of atoms of each element is:

Number of potassium, K atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms    

Number of carbon, C atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Number of nitrogen, N atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = Number of gold, Au atoms+Number of potassium, K atoms +Number of carbon, C atoms + Number of nitrogen, N atoms

Total number of atoms in KAu(CN)_2 = 6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = 39.96\times 10^{20} atoms

Hence, the total number of atoms in KAu(CN)_2 is 3.996\times 10^{21} atoms.

7 0
2 years ago
To determine the concentration of ethanol in cognac a 5.00 mL sample of the cognac is diluted to 0.500 L. Analysis of the dilute
julia-pushkina [17]

Answer : The molar concentration of ethanol in the undiluted cognac is 8.44 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molar concentration of undiluted cognac = ?

M_2 = molar concentration of diluted cognac = 0.0844 M

V_1 =  volume of undiluted cognac = 5.00 mL = 0.005 L

V_2 = volume of diluted cognac = 0.500 L

Now put all the given values in the above law, we get molar concentration of ethanol in the undiluted cognac.

M_1\times 0.005L=0.0844M\times 0.500L

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4 0
2 years ago
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Answer:

An airplane

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An airplane because of its position .

5 0
2 years ago
You can identify a metal by carefully determining its density. A 8.44 g piece of an unknown metal is 1.25 cm long, 2.50 cm wide,
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4 0
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Answer:

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