Explain why c6h5ch2ch2br is not formed during the radical bromination of c6h5ch2ch3. select the single best answer.
1 answer:
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Answer: one simple distillation column is required to separate the stream into five pure products. With four different flat bottom flask, for collection of the distilled products
Explanation: simple distillation works with the difference in boiling points of the liquid to be separated. For the separation of five different constituent to be possible, we have to know the boiling points of the constituents.
For your understanding, let's define constituents in the liquid to be A, B, C, D, E. And the boiling points increases respectively. Start by heating the liquid to the boiling point of A to extract A. After a while check if the constituents A is still dropping in the flat bottom flask, if it has stopped dropping, it simply means that we have extracted all A constituents in the liquid, label the Flask A. Get another flask to extract constituent B.
Heat the mixture to the boiling point of B, after a while check if constituent B is still dropping in the flat bottom flask, if it has stopped dropping,it means that we have extracted all B constituent in the liquid, label the Flask B. Get another flask for C.
Repeat the same process for C and D.
After Extracting D we don't need to distillate E because we already have a pure form of E inside to the conical flask.
SEE PICTURE TO UNDERSTAND WHAT A SIMPLE DISTILLATION LOOKS LIKE
Answer:
A. Optical fibers transmit light signals in high-speed communications.
Explanation:
You didn't include the image, but it probably showed light bouncing off the sides as in the diagram below.
It demonstrates how optical fibers transmit light signals in high-speed communications.
B is wrong. Satellites communicate by radio waves.
C is wrong. Solar cells convert light energy to
D is wrong. Power plants transmit electrical energy to homes through copper wires.
<u>Answer:</u> The equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.
<u>Explanation:</u>
We are given:
Initial concentration of sulfur dioxide = 0.500 M
Initial concentration of nitrogen dioxide = 0.500 M
Initial concentration of sulfur trioxide = 0.00500 M
Initial concentration of nitrogen monoxide = 0.00500 M
The chemical reaction follows:
<u>Initial:</u> 0.500 0.500 0.005 0.005
<u>At eqllm:</u> 0.500-x 0.500-x 0.005+x 0.005+x
The expression of equilibrium constant for the above reaction follows:
We are given:
Putting values in above equation, we get:
Neglecting the value of x = 1.37, because change cannot be greater than the initial concentration
So, equilibrium concentration of sulfur dioxide =
Equilibrium concentration of nitrogen dioxide =
Equilibrium concentration of sulfur trioxide =
Equilibrium concentration of nitrogen monoxide =
Hence, the equilibrium concentration of sulfur dioxide, nitrogen dioxide, sulfur trioxide, nitrogen monoxide is 0.196 M, 0.196 M, 0.309 M and 0.309 M respectively.