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Fynjy0 [20]
2 years ago
6

Gordon wrote this passage about mechanical waves for his physics class. But he got most of his facts mixed up. Only one sentence

is correct. Which sentence is it?
A) Mechanical waves don’t need a medium to travel. When they travel through a vacuum, mechanical waves are oval-shaped. They’re either transverse or double transverse waves.

B) Mechanical waves can apply pressure to and push on objects in their path.

C) But they travel slower in denser mediums.
Chemistry
2 answers:
Zinaida [17]2 years ago
4 0

Answer: The correct answer is "Mechanical waves can apply pressure to and push on objects in their path".

Explanation:

Mechanical wave is wave in which there is an oscillation of the wave. The energy is transferred through a medium. Mechanical waves can apply pressure to and push on their path. Only the energy is transferred not the matter.

Mechanical waves are of three types: Transverse wave, Longitudinal wave and Surface wave. The examples of the mechanical wave are sound wave and water wave.

Sound is a pressure disturbance which travels through a medium. It consists of compression and rarefaction.

The mechanical waves need a medium for their propagation. They travel faster in denser medium.

Therefore, the correct option is (B).

Basile [38]2 years ago
4 0

Answer:

B) Mechanical waves can apply pressure to and push on objects in their path.

Explanation:

I just took the test and I got it right.

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A solution is prepared by condensing 4.00 l of a gas, measured at 27°c and 748 mmhg pressure, into 58.0 g of benzene. calculate
fgiga [73]
First, we are using the ideal gas law to get n the number of moles:

PV = nRT

when P is the pressure = 748 mmHg/760 = 0.984 atm

V is the volume = 4 L

R is ideal gas constant = 0.0821

T is the temperature in Kelvin = 300 K

∴ n =  0.984atm*4L/0.0821*300

       = 0.1598 moles

when the concentration = moles * (1000g / mass)

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                                         = 2.755 M

when the freezing point = 5.5 °C

and Kf = - 5.12 °C/m

∴ the freezing point for the solution = 5.5 °C + (Kf*m)

                                                            = 5.5 °C - (5.12°C/m * 2.755m)

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1 year ago
Read 2 more answers
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Explanation:

6 0
2 years ago
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<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

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According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

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(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

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Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

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