Answer:
B 1.23 g/cc
Explanation:
For something to float on seawater, the density must be less than 1.03 g/mL. If the object sinks, the density is greater than 1.03 g/mL.
Let’s examine the answer choices. Keep in mind, the ice berg is mostly below the water level.
A. 0.88 g/cc
This is less than 1.03 g/cc, which would result in floating.
B. 1.23 g/cc
This is the best answer choice. The iceberg is mostly beneath the water, but some of it is exposed. The density is greater than 1.03 g/mL, but not so much greater that it would immediately sink.
C. 0.23 g/cc
This is less than 1.03 g/cc, which would produce floating.
D. 4.14 g/cc
This is much greater than 1.03 g/cc and the result would be sinking.
<u>Given:</u>
Moles of gas, n = 1.50 moles
Volume of cylinder, V = 15.0 L
Initial temperature, T1 = 100 C = (100 + 273)K = 373 K
Final temperature, T2 = 150 C = (150+273)K = 423 K
<u>To determine:</u>
The pressure ratio
<u>Explanation:</u>
Based on ideal gas law:
PV = nRT
P= pressure; V = volume; n = moles; R = gas constant and T = temperature
under constant n and V we have:
P/T = constant
(or) P1/P2 = T1/T2 ---------------Gay Lussac's law
where P1 and P2 are the initial and final pressures respectively
substituting for T1 and T2 we get:
P1/P2 = 373/423 = 0.882
Thus, the ratio of P2/P1 = 1.13
Ans: The pressure ratio is 1.13
a.
Acids react with bases and give salt and water and the products.
Hence, HCl reacts with NaOH and gives NaCl salt and H₂O as the products. The reaction is,
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
To balance the reaction equation, both sides hould have same number of elements.
Left hand side, Right hand side,
H atoms = 2 H atoms = 2
Cl atoms = 1 Cl atoms = 1
Na atoms = 1 Na atoms = 1
O atoms = 1 O atoms = 1
Hence, the reaction equation is already balanced.
b.
Molarity (M)= moles of solute (mol) / Volume of the solution (L)
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
Molarity of NaOH = <span>0.13 M
</span>Volume of NaOH added = <span>43.7 mL
Hence, moles of NaOH added = 0.13 M x 43.7 x 10</span>⁻³ L
= 5.681 x 10⁻³ mol
Stoichiometric ratio between NaOH and HCl is 1 : 1
Hence, moles of HCl = moles of NaOH
= 5.681 x 10⁻³ mol
5.681 x 10⁻³ mol of HCl was in <span>26.9 mL.
Hence, molarity of HCl = </span>5.681 x 10⁻³ mol / 26.9 x 10⁻³ L
= 0.21 M
Answer:
<em><u>= - 0.38 eV</u></em>
Explanation:
Using Bohr's equation for the energy of an electron in the nth orbital,
E = -13.6 
Where E = energy level in electron volt (eV)
Z = atomic number of atom
n = principal state
Given that n = 6
⇒ E = -13.6 × 
<em><u>= - 0.38 eV</u></em>
<em><u></u></em>
<em>Hope this was helpful.</em>
<em><u></u></em>
Answer:
Neon
Explanation:
1s² 2s² 2p⁶ 3s¹ or [Ne] 3s¹
The outer most shell is the 3s¹.
For this atom to achieve stability, if it loses the electron in the 3s shell, it would resemble an inert element with a complete octet configuration. Therefore, the atom would be like:
1s² 2s² 2p⁶ which is the configuration of Ne
