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1 year ago

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A 5.00-wt% aqueous sulfuric acid solution (p=1.03 g/ml) flows through a 45-m long pipe with a 6.0 cm diameter at a rate of 82 L/

min. a) What is the molarity of sulfuric acid in the solution? b) How long in seconds) would it take to fill a 55-gallon drum, and how much sulfuric acid (lbm) would the drum contain? c) The mean velocity of a fluid in a pipe equals the volumetric flow rate divided by the cross-sectional area normal to the direction of flow. Use this information to estimate how long (in seconds) it takes the solution to flow from the pipe inlet to the outlet.

1 answer:

Anni [7]1 year ago

6 0

Answer:

Explanation:

a )

5 gram of sulfuric acid in 100 gram of solution

volume of 100 gram of solution = 100 / 1.03 ml

= 97.08 ml = .097 L

5 gram of sulfuric acid = 5 / 98 moles = .051 moles

.051 moles in .097 L solution

molarity = .051 / .097 = .525 M .

b ) 55 gallon = 3.7854 x 55 L = 208 L

rate of flow = 82 L / min

time taken to fill the drum = 208 / 82 min = 2.536 min .

volume of sulfuric acid = 208 L

mass = volume x density = 208 x 1000 x 1.03 gram = 214.24 kg

214.24 kg = 214.24 x 2.2 lb = 471.33 lb

c )

cross sectional area = 3.14 x 3² = 28.26 cm²

rate of flow = 82 L / min = 82 x 1000 cm³ / min

= 82000 / 60 cm³ / sec = 1366.67 cm³ / s

velocity = 82 x 1000 / 1366.67 = 60 cm / s = .6 m / s

length of pipe = 45 m

time taken = 45 / .6 = 75 s

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