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Aleonysh [2.5K]
2 years ago
10

Which compound is an exception to the octet rule?

Chemistry
2 answers:
slavikrds [6]2 years ago
8 0

Answer:

the answer is ClF3 on edge

Explanation:

viva [34]2 years ago
5 0

Answer:

CIF3

Explanation:

I just took the test

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In a fixed cylinder are 3moles of oxygen gas at 300Kelvin and 1.25atm. What is the volume of the container?
vladimir2022 [97]

Answer:

The volume of the container is 59.112 L

Explanation:

Given that,

Number of moles of Oxygen, n = 3

Temperature of the gas, T = 300 K

Pressure of the gas, P = 1.25 atm

We need to find the volume of the container. For a gas, we know that,

PV = nRT

V is volume

R is gas constant, R =  0.0821 atm-L/mol-K

So,

V=\dfrac{nRT}{P}\\\\V=\dfrac{3\ mol\times 0.0821\ L-atm/mol-K \times 300\ K}{1.25\ atm}\\\\V=59.112\ L

So, the volume of the container is 59.112 L

6 0
1 year ago
How many atoms of fluorine are in ZrF4
harkovskaia [24]

Answer:

Zirconium tetrafluoride has 4 atoms of flourine and 1 atom of Zirconium

3 0
2 years ago
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. NH4l, CoBr3, Na2
seraphim [82]
Answer:

NaI > Na2SO4 > Co Br3

meaning that NaI has the highest freezing point, and Co Br3 has the lowest freezing point.

Explanation:

The freezing point depression is a colligative property.

That means that it depends on the number of solute particles dissolved.

The formula to calculate the freezing point depression of a solution of a non volatile solute is:

ΔTf = i * Kf * m

Where kf is a constant, m is the molality and i is the van't Hoff factor.

Molality, which is number of moles per kg of solvent, counts for the number of moles dissolved and the van't Hoff factor multipllies according for molecules that dissociate.

The higher the number of molecules that dissociate, the higher the van't Hoff, the greater the freezing point depression and the lower the freezing point.

As the question states that you assume equal concentrations (molality) and complete dissociation you just must find the number of ions generated by each solute, in this way:

NH4 I → NH4(+) + I(-) => 2 ions

Co Br3 → Co(+) + 3 Br(-) => 4 ions

Na2SO4 → 2Na(+) + SO4(2-) => 3 ions.

So, Co Br3 is the solute that generate more particles and that solution will exhibit the lowest freezing point among the options given, Na2SO4 is next and the NaI is the third. Ordering the freezing point from higher to lower the rank is NaI > Na2SO4 > CoBr3, which is the answer given.
4 0
1 year ago
What is the molarity of solution made by diluting 26.5 ml of 6.00m hno3 to a volume of 250 ml?
Sever21 [200]
The  molarity  of    solution  made  by  diluting   26.5ml  of  6.0ml  hno3  to  a  volume  of  250ml  is  calculated  using  the  following  formula

M1V1  =  M2V2,   where 

M1  =  molality  1 (6.00m)
V1=  volume  1 (26.5  ml)
M2 = molarity  2(?)
v2=volume  2   (250)

M2 =  M1V1/V2

M2=  6  x26.5/250  =  0.636 M




3 0
1 year ago
Read 2 more answers
Draw a lewis structure for so2 in which all atoms obey the octet rule. show formal charges. do not consider ringed structures.
Aleonysh [2.5K]
Formal charge = valence electron - bonds - dots.
double bonded oxygen = 6-2-
4 so it is 0
single bonded oxygen = 6-1-6 so it is -1
sulfur = 6-3-2 so it is +1

6 0
1 year ago
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