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2 years ago

Which example best demonstrates stewardship of the atmosphere

Chemistry

1 answer:

Margarita [4]2 years ago

3 0

Incomplete question. However, I provided a specific example of stewardship of the atmosphere.

Explanation:

First, note that the term stewardship refers to the belief that humans are obligated to take care and look after our environment (which includes the atmosphere.

An example of this is: deciding to change our mode of transportation: What this entails is that we may decide to switch to riding a bicycle to places rather than going by car. By so doing you will be reducing the number of greenhouse gases emitted into the environment as bicycles do not emit harmful gases when used.

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If Co(NH3)63+ has a λmax at 440 nm, calculate ΔE for the complex. A) 2.72 x 10-4 kJ/mol B) 4.52 x 10-2 kJ/mol C) 2.72 x 10 2 kJ/

riadik2000 [5.3K]

Answer: The energy of the complex is $2.72\times 10^2kJ$

Explanation:

To calculate the energy of the complex, we use the equation given by Planck which is:

$\Delta E=\frac{N_Ahc}{\lambda}$

where,

$\lambda$ = Wavelength of the complex = $440nm=4.40\times 10^{-7}m$ (Conversion factor: $1m=10^9nm$ )

h = Planck's constant = $6.624\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

$\Delta E$ = energy of the complex

Putting values in above equation, we get:

$\Delta E=\frac{6.022\times 10^{23}\times 6.624\times 10^{-34}\times 3\times 10^8}{4.40\times 10^{-7}}\\\\\Delta E=2.72\times 10^{5}J=2.72\times 10^2kJ$

Conversion factor used: 1 kJ = 1000 J

Hence, the energy of the complex is $2.72\times 10^2kJ$

5 0

2 years ago

Carbon monoxide and molecular oxygen react to form carbon dioxide. A 50.0 L reactor at 25.0 oC is charged with 1.00 bar of CO. T

Umnica [9.8K]

Answer:

CO = zero

CO2 =1 bar

O2 = 2.02 bar

Explanation:

We are given

initial pressure of CO = 1bar

total pressure = 3.52 bar

so initial pressure of O2 = 3.52 - 1 = 2.52 bar

the reaction is

2CO + O2 → 2CO2

using the unitary method

2 moles of CO2 → 1 mole of O2

1 bar of CO → $\frac{1}{2} * 1= 0.5 bar$ (required)

but we have more oxygen present , that means CO is the limiting reagent

Final pressure of CO will be zero as it is the limiting reagent so it will be consumed completely
1 bar of CO → $\frac{2mol CO2}{2mol CO} * 1= 1 bar$ of CO2
2.52 bar O2 (initially) - 0.5 bar (reacted) = 2.02bar O2

6 0

2 years ago

Which choice(s) correctly rank(s) the bonds in terms of increasing polarity?

Marina CMI [18]

Answer:

(II) only correctly rank the bonds in terms of increasing polarity.

Explanation:

Bond polarity is proportional to difference in electronegativity between bonded atoms.

Atoms Electronegativity Bond Electronegativity difference

Cl 3.0 Cl-F 1.0

Br 2.8 Br-Cl 0.2

F 4.0 Cl-Cl 0

H 2.1 H-C 0.4

C 2.5 H-N 0.9

N 3.0 H-O 1.4

O 3.5 Br-F 1.2

I 2.7 I-F 1.3

Si 1.9 Cl-F 1.0

P 2.2 Si-Cl 1.1

Si-P 0.3

Si-C 0.6

Si-F 2.1

So, clearly, order of increasing polarity : O-H > N-H > C-H

So, (II) only correctly rank the bonds in terms of increasing polarity

4 0

2 years ago

What is the molarity of a solution that contains 2.35 g of nh3 in 0.0500 l of solution?

tankabanditka [31]

The molarity is the number of moles in 1 L of the solution.
The mass of NH₃ given - 2.35 g
Molar mass of NH₃ - 17 g/mol
The number of NH₃ moles in 2.35 g - 2.35 g / 17 g/mol = 0.138 mol
The number of moles in 0.05 L solution - 0.138 mol
Therefore number of moles in 1 L - 0.138 mol / 0.05 L x 1L = 2.76 mol
Therefore molarity of NH₃ - 2.76 M

3 0

2 years ago

Read 2 more answers

Write the balanced half-equation describing the oxidation of mercury to hgo in a basic aqueous solution. Please include the stat

Cloud [144]

Answer:

$Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-$