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Elza [17]
2 years ago
9

Carbon dioxide (co2) is readily soluble in water, according to the equation co2 + h2o ↔ h2co3. carbonic acid (h2co3) is a weak a

cid. respiring cells release co2 into the bloodstream. what will be the effect on the ph of blood as that blood first comes in contact with respiring cells?
Chemistry
1 answer:
bixtya [17]2 years ago
6 0

Blood is a buffer solution of bicarbonate (HCO₃⁻) and carbon dioxide (CO₂). The Henderson equation which relates the concentration of HCO₃⁻ and CO₂ is given below:

p^{H}=p^{k_{a} } = p^{H} + log\frac{HCO_{3}^{-}  }{CO_{2}  }.

Respiring cell releases CO₂ in blood stream and that CO₂ on reaction with water molecule produces H₂CO₃ which is a weak base and its conjugate base is  HCO₃⁻.

CO₂ + 2H₂O⇄ HCO₃⁻ + H₃O⁺

pH of the buffer solution (the blood) depends only on the ratio of the amount of CO₂ to the amount of HCO³⁻. [So, due to respiration produced CO₂ will get dissolved in water and favours the equilibrium towards forward direction. Then immediately HCO₃⁻ reacts with HCO₃⁻ and starts producing CO₂.]This ratio remains relatively constant because the concentrations HCO3- and CO2 are very large compared to the amount of CO₂ produced to the blood from respiring cells. So, p^{H} of blood does not change.

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Answer:

Explanation:

Here we have the mass of CO₂ added = 340 g

From

Number \, of \, moles = \frac{Mass}{Molar \, mass}

We have, where the molar mass of CO₂ is 44.01 g/mol

Therefore,

Number \, of \, moles = \frac{340}{44.01} = 7.73 \, \, \, moles

71. Included drawing attached

72. Here we have the pressure of the gas given by Charles law which can be resented as follows;

\frac{P_1}{P_2} =\frac{T_1}{T_2}

Where:

P₁ = Initial pressure = 6.1 atmospheres

P₂ = Final pressure

T₁ = Initial Temperature = 293 K

T₂ = Initial Temperature = 313 K

Therefore,

P_2= T_2 \times \frac{P_1}{T_1} = 313 \times \frac{6.1}{293} = 3.312 \, \, \, atmospheres

 

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2. If 2.50g of sodium hydroxide is being reacted with 4.30g of magnesium chloride, how many grams of magnesium hydroxide would b
Virty [35]

Answer:

1.822 g of magnesium hydroxide would be produced.

Explanation:

Balanced reaction: 2NaOH+MgCl_{2}\rightarrow Mg(OH)_{2}+2NaCl

     Compound                                 Molar mass (g/mol)

         NaOH                                           39.997

         MgCl_{2}                                           95.211

        Mg(OH)_{2}                                        58.3197

So, 2.50 g of NaOH = \frac{2.50}{39.997} mol of NaOH = 0.0625 mol of NaOH

      4.30 g of MgCl_{2}  = \frac{4.30}{95.211} mol of MgCl_{2} = 0.0452 mol of MgCl_{2}

According to balanced equation-

2 mol of NaOH produce 1 mol of Mg(OH)_{2}    

So, 0.0625 mol of NaOH produce (\frac{0.0625}{2}) mol of NaOH or 0.03125 mol of NaOH

1 mol of MgCl_{2} produces 1 mol of Mg(OH)_{2}

So, 0.0452 mol of MgCl_{2} produce 0.0452 mol of Mg(OH)_{2}

As least number of moles of Mg(OH)_{2} are produced from NaOH therefore NaOH is the limiting reagent.

So, amount of Mg(OH)_{2} would be produced = 0.03125 mol

                                                                           = (0.03125\times 58.3197) g

                                                                           = 1.822 g

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2 years ago
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6.An acid-base indicator is usually a weak acid with a characteristic color in the protonated and deprotonated forms. Because br
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Answer:

At equal concentration of HBCG and BCG^-, the colour is green. This colour first appears at pH = 3.8

Explanation:

HBCG is an indicator that is prepared by dissolving the solid in ethanol.

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