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Elza [17]
2 years ago
9

Carbon dioxide (co2) is readily soluble in water, according to the equation co2 + h2o ↔ h2co3. carbonic acid (h2co3) is a weak a

cid. respiring cells release co2 into the bloodstream. what will be the effect on the ph of blood as that blood first comes in contact with respiring cells?
Chemistry
1 answer:
bixtya [17]2 years ago
6 0

Blood is a buffer solution of bicarbonate (HCO₃⁻) and carbon dioxide (CO₂). The Henderson equation which relates the concentration of HCO₃⁻ and CO₂ is given below:

p^{H}=p^{k_{a} } = p^{H} + log\frac{HCO_{3}^{-}  }{CO_{2}  }.

Respiring cell releases CO₂ in blood stream and that CO₂ on reaction with water molecule produces H₂CO₃ which is a weak base and its conjugate base is  HCO₃⁻.

CO₂ + 2H₂O⇄ HCO₃⁻ + H₃O⁺

pH of the buffer solution (the blood) depends only on the ratio of the amount of CO₂ to the amount of HCO³⁻. [So, due to respiration produced CO₂ will get dissolved in water and favours the equilibrium towards forward direction. Then immediately HCO₃⁻ reacts with HCO₃⁻ and starts producing CO₂.]This ratio remains relatively constant because the concentrations HCO3- and CO2 are very large compared to the amount of CO₂ produced to the blood from respiring cells. So, p^{H} of blood does not change.

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Consider the element in the periodic table that is directly to the right of the element identified in part (a). Would the 1s pea
astraxan [27]

The question is incomplete. Here is the complete question.

The photoelectron spectroscopy is shwon below.

(a) Based on the photoelectron spectrum, identify the unknown element and write its electron configuration.

(b) Consider the element in the periodic table that is directly to the right of the element identified in part (a). Would the 1s peak of this element appear to the left of, the right of, or in the same position as the 1s peak of the element in part (a)? Explain your reasoning.

Answer and Explanation: <u>Photoelectron</u> <u>Spectroscopy</u> is a method of determinining the relative energy of electrons in atoms and molecules.

It is based on the <em>photoelectric effect: </em>when a radiation energy incides on a substance, an electron is ejected from it. If we know the kinetic energy of the ejected electron, known as photoelectrons, and the energy of the incident radiation, it is possible to find the energy of the electron in the substance.

The energy needed to eject an electron from the sample is called <em>Binding Energy</em> and in an atom, depends on which shell the electron is: valence eletrons (outermost shell), binding energy is lower; core eletrons (innermost shell), binding energy is highest.

In the graph, vertical axis shows 5 peaks for different energies. The peak closer to the origin, the leftmost peak, correspond to the 1s subshell, since their are closest to the nucleus, and so, has the highest binding energy.

Following from left to the right, we noticed:

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1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{3}

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(b) The element to the right of element P is Sulfur (S). The peak 1s of sulfur will appear in the same position as the 1s peak of Phosphorus, because the elements in the Periodic Table are grouped according to certain properties. Elements in the same horizontal line are elements in the same period, which one of the characteristics is they have the same total number of electron shells.

4 0
1 year ago
Alexandra decides to climb Mt. Krumpett, which is 5000 m high. She determines that this will require a total of 1350 kcal of ene
Kisachek [45]
Alexandra requires a total energy of 1350 kcal for the climb
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each bar contains;
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8 0
2 years ago
150.0 grams of AsF3 were reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2 produced, in
Kamila [148]
The chemical reaction would be written as 

2 AsF3<span> + 3 CCl4 = 2 AsCl3 + 3 CCl2F2
</span>
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150 g AsF3 ( 1 mol / 131.92 g) = 1.14 mol AsF3
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7 0
1 year ago
175 mL of Cl2 gas is held in a flexible vessel at
Gnoma [55]

Answer:

V₂ = 15.6 L

Explanation:

Given data:

Initial volume = 175 mL  (0.175 L)

Initial pressure = 1 atm

Initial temperature = 273 K

Final temperature = -5°C (-5+273 = 268 K)

Final volume = ?

Final pressure = 1.16 kpa (1.16/101=0.011 atm)

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 0.175 L × 268 K / 273 K × 0.011 atm

V₂ = 46.9 L / 3.003

V₂ = 15.6 L

7 0
1 year ago
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