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aniked [119]
2 years ago
5

A gold atom has a radius of 145 pm. If you could string gold atoms like beads on a thread, how many atoms would you need to have

a necklace 36 cm long?
Chemistry
1 answer:
dalvyx [7]2 years ago
8 0
First we have to convert:145 pm = 145 * 10^(-12) m36 cm = 360 mm = 360 * 10^(-3) mn = 360 * 10^(-3) m / 145 * 10^(-12) m = = 360 * 10^(-3) * 10^(12) / 145 = = 2.482758621 * 10^(9) or:2,482,758,621 atoms.

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O: 1*2 = 2*1 
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<span>answer C hope you get it right</span>
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Give the major organic product of the reaction of o-methylaniline with benzenediazonium chloride [(phn≡n)+ cl-].
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Using the following standard reduction potentials, Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Ni2+(aq) + 2 e- → Ni(s) E° = -0.23 V ca
lina2011 [118]

<u>Answer:</u> The above reaction is non-spontaneous.

<u>Explanation:</u>

For the given chemical reaction:

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3 0
2 years ago
Some hydrogen gas is enclosed within a chamber being held at 200∘C∘C with a volume of 0.0250 m3m3. The chamber is fitted with a
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Answer:

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Explanation:

Step 1: Data given

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The pressure reduce to 0.950 *10^6 Pa

The temperature stays constant at 200 °C

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⇒with V1 = the initial volume = 25 L

⇒with P2 = the final pressure = 0.950 * 10^6 Pa

⇒with V2 = the final volume = TO BE DETERMINED

1.50 *10^6 Pa * 25 L = 0.950 *10^6 Pa * V2

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3 0
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