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aniked [119]
2 years ago
5

A gold atom has a radius of 145 pm. If you could string gold atoms like beads on a thread, how many atoms would you need to have

a necklace 36 cm long?
Chemistry
1 answer:
dalvyx [7]2 years ago
8 0
First we have to convert:145 pm = 145 * 10^(-12) m36 cm = 360 mm = 360 * 10^(-3) mn = 360 * 10^(-3) m / 145 * 10^(-12) m = = 360 * 10^(-3) * 10^(12) / 145 = = 2.482758621 * 10^(9) or:2,482,758,621 atoms.

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Answer:

0.5594\ \text{L}

Explanation:

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Molarity is given by

M=\dfrac{\text{mol}}{\text{Volume of solution in }NaI}\\\Rightarrow \text{Volume of solution in }NaI=\dfrac{0.405}{0.724}\\\Rightarrow \text{Volume of solution in }NaI=0.5594\ \text{L}

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2 years ago
Calculate the amount of heat necessary to raise the temperature of 135.0 g of water from 50.4°F to 85.0°F. The specific heat of
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Here we have to calculate the heat required to raise the temperature of water from 85.0 ⁰F to 50.4 ⁰F.

10.857 kJ heat will be needed to raise the temperature from 50.4 ⁰F to 85.0 ⁰F

The amount of heat required to raise the temperature can be obtained from the equation H = m×s×(t₂-t₁).

Where H = Heat, s  =specific gravity = 4.184 J/g.⁰C, m = mass = 135.0 g, t₁ (initial temperature) = 50.4 ⁰F or 10.222 ⁰C and t₂ (final temperature) = 85.0⁰F or 29.444 ⁰C.

On plugging the values we get:

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\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3

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