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erastovalidia [21]
2 years ago
13

Daniel Harris has always enjoyed eating tuna fish. Unfortunately, a study of the mercury content of canned tuna in 2010 found th

at chunk white tuna contains 0.6 ppm Hg and chunk light tuna contains 0.14 ppm.2 The U.S. Environmental Protection Agency (EPA) recommends no more than 0.1 μg Hg/kg body weight per day. A person weighs 63 kg . How often may the person eat a can containing 6 ounces (16 oz=1 lb) of chunk white tuna so that they do not average more than 0.1 μg Hg/kg body weight per day?
А The person can consume one 6 oz can of chunk white tuna every_______ days.
If the person switches to chunk light tuna, how often can they eat one can?
The person can consume one 6 oz can of chunk light tuna every_______ days.
Chemistry
1 answer:
meriva2 years ago
4 0
That would be 3 days 6 oz of tuna
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What volume (ml) of a 0.2450 m koh(aq) solution is required to completely neutralize 55.25 ml of a 0.5440 m h3po4(aq) solution?
Nonamiya [84]
<span>Answer: It depends on what came after "0.5440 M H...". If it was a monoprotic acid, like HCl, the calculation would go like this: (55.25 mL) x (0.5440 M acid) x (1 mol KOH / 1 mol acid) / (0.2450 M KOH) = 122.7 mL KOH If it was a diprotic acid, like H2SO4, like this: (55.25 mL) x (0.5440 M acid) x (2 mol KOH / 1 mol acid) / (0.2450 M KOH) = 245.4 mL KOH If it was a triprotic acid, like H3PO4, like this: (55.25 mL) x (0.5440 M acid) x (3 mol KOH / 1 mol acid) / (0.2450 M KOH) = 368.0 mL KOH</span>
5 0
2 years ago
If 3.491 grams of the precipitate was formed, how many moles of strontium bromide were reacted
AVprozaik [17]
The balanced chemical equation that represents the reaction is as follows:
 <span>SrBr2(aq) + 2AgNO3(aq) → Sr(NO3)2(aq) + 2AgBr(s) 
</span>
From the periodic table:
mass of silver = 108 grams
mass of bromine = 80 grams

molar mass of silver bromide = 108 + 80 = 188 grams

number of moles = mass / molar mass
number of moles of produced precipitate = 3.491/188 = 0.018 moles

From the balanced equation:
1 mole of  strontium bromide produces 2 moles of silver bromide. Therefore, to calculate the number of moles of <span>strontium bromide that produces 0.018 moles of silver bromide, you will just do a cross multiplication as follows:
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4 0
2 years ago
A student adds solid KCl to water in a flask. The flask is sealed with a stopper and thoroughly shaken until no more solid KCl d
AlladinOne [14]

Answer:

Option (A) saturated and is at equilibrium with the solid KCl

Explanation:

A saturated solution is a solution which can not dissolve more solute in the solution.

From the question given above, we can see that the solution is saturated as it can not further dissolve any more KCl as some KCl is still visible in the flask.

Equilibrium is attained in a chemical reaction when there is no observable change in the reaction system with time. Now, observing the question given we can see that there is no change in flask as some KCl is still visible even after thorough shaking. This simply implies that the solution is in equilibrium with the KCl solid as no further dissolution occurs.

4 0
2 years ago
SEP Use Models Why does the number of electrons in each principal energy shell increase as the number of the shell increases?
zlopas [31]

Answer:

See explanation

Explanation:

The number of electrons in each principal energy shell increases as the number of shells increases because more electronic orbitals become available to accommodate the electrons.

For instance, the n= 2 level only accommodates eight electrons in the s and p orbitals whereas the n=3 level accommodates 18 electrons in s, p and d orbitals respectively.

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4 0
1 year ago
HBrO (aq) + H2O (l) ⇋ H3O+ (aq) + BrO- (aq)
joja [24]

Answer:

6.24 x 10-3 M

Explanation:

Hello,

In this case, for the given dissociation, we have the following equilibrium expression in terms of the law of mass action:

Ka=\frac{[H_3O^+][BrO^-]}{[HBrO]}

Of course, water is excluded as it is liquid and the concentration of aqueous species should be considered only. In such a way, in terms of the change x, we rewrite the expression considering an ICE table and the initial concentration of HBrO that is 0.749 M:

5.2x10^{-5}=\frac{x*x}{0.749-x}

Thus, we obtain a quadratic equation whose solution is:

x_1=-0.00627M\\x_2=0.00624M

Clearly, the solution is 0.00624 M as no negative concentrations are allowed, so the concentration of BrO⁻ is 6.24 x 10-3 M.

Best regards.

4 0
2 years ago
Read 2 more answers
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