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ivolga24 [154]
2 years ago
14

How many moles of tungsten (W,183.85 g/mol) are in 415 grams of tungsten?

Chemistry
2 answers:
ozzi2 years ago
8 0
2.25739773716275. I used a calculator during class today to get this answer, and I am pretty sure it is right, hope it helps. 
Andru [333]2 years ago
7 0

Answer : The moles of tungsten is, 2.257 moles

Explanation : Given,

Mass of tungsten = 415 grams

Molar mass of tungsten = 183.85 g/mole

Formula used :

\text{Moles of tungsten}=\frac{\text{Given mass of tungsten}}{\text{Molar mass of tungsten}}

Now put all the given values in this formula, we get :

\text{Moles of tungsten}=\frac{415g}{183.85g/mole}=2.257moles

Therefore, the moles of tungsten is, 2.257 moles

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Answer is: line be long 3,011·10¹³ kilometers.
diametar of virus = 5·10⁻⁶ cm ÷ 100000 = 5·10⁻¹¹ km.
line lenght = 5·10⁻¹¹ km · 6,023·10²³.
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Avogadro number = 6,023·10²³.
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2 years ago
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What was the original volume of a gas if heating it from 22k to 85k produced a volume of 3.8 liters?
mel-nik [20]

Answer: the original volume was 0.98L

Explanation:

V1 =?

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3 0
1 year ago
You work for a cutlery manufacturer who wants to electrolytically precipitate 0.500 g of silver onto each piece of a batch of 25
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Answer:

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

Explanation:

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Moles of AgCN = n  = \frac{125 g}{134 g/mol}=0.9328 mol

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2 years ago
In the manufacture of paper, logs are cut into small chips, which are stirred into an alkaline solution that dissolves several o
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The estimated feed rate of logs is 14.3 logs/min.

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That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.

Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.

To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.

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n=\frac{supply}{M_{log}}=\frac{3617 tons/day}{387.5 lbm}*\frac{2204lbm}{1ton}\\\\n=20573 logs/day=14.3 logs/min

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Answer:

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