A 0.050 M solution of AlCl3 had an observed osmotic pressure of 3.85 atm at 20 ∘C . Calculate the van't Hoff factor i for AlCl3.
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1)we need a balanced equation: CuSO₄ + Zn ---> ZnSO₄ + Cu
2) we need to convert the grams of CuSO₄ to moles using the molar mass.
molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol
3) convert moles of CuSO₄ to moles of Cu
4) convert moles of Cu to grams using it's molar mass.
molar mass Cu= 63.5 g/mol
I did it step-by-step as the explanation but you can do all of this in one step.
2) we need to convert the grams of CuSO₄ to moles using the molar mass.
molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol
3) convert moles of CuSO₄ to moles of Cu
4) convert moles of Cu to grams using it's molar mass.
molar mass Cu= 63.5 g/mol
I did it step-by-step as the explanation but you can do all of this in one step.
Answer:- 1840 g.
Solution:- We have been given with 3.35 moles of and asked to calculate it's mass.
To convert the moles to grams we multiply the moles by the molar mass of the compound. Molar mass of the compound is the sum of atomic masses of all the atoms present in it.
molar mass of = atomic mass of Hg + 2(atomic mass of I) + 6(atomic mass of O)
= 200.59+2(126.90)+6(16.00)
= 200.59+253.80+96.00
= 550.39 gram per mol
Let's multiply the given moles by the molar mass:
= 1843.8 g
Since, there are three sig figs in the given moles of compound, we need to round the calculated my to three sig figs also. So, on rounding off to three sig figs the mass becomes 1840 g.