Answer:
The correct option is: Isoleucine
Explanation:
Peptides are the biological molecules containing amino acids which are linked together by peptide bonds. A polypeptide is a peptide chain in which more than 20 amino acids are linked together by peptide bond.
All polypeptide chains have a N-terminal and a C-terminal.
The N-terminal of a polypeptide is also known as the amino terminal. The N-terminal has a free amine group, which is generally on the left hand side of the polypeptide chain.
Therefore, the N-terminal or the amino terminal of the given polypeptide is Isoleucine (I).
Answer:
The correct order will be
a. Transfer the measured amount of NaCl to the volumetric flask.
e. Dissolve the NaCl in less than 250 mL of water and mix well.
b. Dilute the solution with water to the 250.0 mL mark.
Explanation:
Preparation of NaCl solution in 250.0 ml volumetric flask:
Add the weighed NaCl directly to volumetric flask and add small amount of water to it and mix it will until all NaCl gets dissolved( if not add small water amount of water more)
After dissolving NaCl add the water upto the mark.
The correct order will be
a. Transfer the measured amount of NaCl to the volumetric flask.
e. Dissolve the NaCl in less than 250 mL of water and mix well.
b. Dilute the solution with water to the 250.0 mL mark.
Answer:
The right solution is "
".
Explanation:
As we know,
1 mole electron = 
Total energy = 
= 
For single electron,
The amount of energy will be:
= 
= 
Answer:
223.08 K
Explanation:
First we <u>convert 173.0 °C to K</u>:
- 173.0 °C + 273.16 = 446.16 K
With the absolute temperature we can use <em>Charles' law</em> to solve this problem:
Where in this case:
We <u>input the data</u>:
- 446.16 K * 50 L = T₂ * 100 L
And <u>solve for T₂</u>:
Answer:
1.06 mL of toluene will be needed.
Explanation:
Equi-molar mixture means equal moles of all the components.
as given the volume of ethyl acetate = 1mL
Density of ethyl acetate = 0.898 g/mL
The relation between density, mass and volume is :

mass=volumeXdensity
mass of ethyl acetate present = 1mL X 0.898g/mL = 0.598 grams
the moles are related to mass as:

For ethyl acetate molar mass = 4X12+8X1+2X16= 88g/mol
moles of ethyl acetate will be:

So we need 0.01 moles of toluene also
For 0.01 moles the mass of toluene required = 0.01 X molar mass of toluene
mass required = 0.01 X 92=0.92grams
for 0.92 grams of toluene volume required will be:
