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S_A_V [24]
1 year ago
5

Convert mass to moles for both reactants. (round to 2 significant figures.) 2.50 g cuci2 equals moles e 0.25 g Al equals moles D

ONE
Chemistry
2 answers:
Marat540 [252]1 year ago
3 0
To convert a mass of a substance to units of moles, we would need the molar mass of the substance since is it describes the mass of one mole of that substance. For CuCl2, the molar mass is 134.45 g/mol. For Al, the atomic mass is 26.98 g/mol.

2.50 g CuCl2 ( 1 mol / 134.45) = 0.019 mol CuCl2
0.25 g Al ( 1 mol / 26.98 g ) = 0.0093 mol Al
PilotLPTM [1.2K]1 year ago
3 0

Answer:

Explanation: CuCl2=0.019

.50 Al = 0.19

on edge

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A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC
diamong [38]

Answer : The pressure in the flask after reaction complete is, 2.4 atm

Explanation :

To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.

PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}

where,

P = final pressure in the flask = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = 25^oC=273+25=298K

V = volume = 4.0 L

n_1 = moles of SO_2 = 0.20 mol

n_2 = moles of O_2 = 0.20 mol

Now put all the given values in the above expression, we get:

P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}

P=2.4atm

Thus, the pressure in the flask after reaction complete is, 2.4 atm

5 0
1 year ago
What is the total E associated with one mole of photons (a unit known as the Einstein) of 3.91x1019 Hz?
sashaice [31]

Answer:

        E=1.56\times 10^{10}J

Explanation:

The<em> energy of a photon</em>, E, can be calculated with the Planck-Einstein equation:

          E=hf

Where:

  • h is Planck's constant 6.626×10⁻³⁴ J.s, and
  • f is the frequency of the photon or electromagnetic radiation.

Substituting with your data:

          E=6.626\times 10^{-34}J.s\times 3.91\times 10^{19}s^{-1}=2.5908\times 10^{-14}J

Now multiply by Avogadro's number to obtain the energy of one mole of photons:

          E=2.5908\times 10^{-14}J\times 6.022\times 10^{23}=1.56\times 10^{10}J

8 0
1 year ago
Which quantity can vary among atoms of the same element?
Wewaii [24]
There is this thing called isotopes
it means that atoms of the same element can have a different number of neutrons.
if there is a change in the no. of neutrons, there will definitely be a change in the mass number.

so the answer is A) mass number
7 0
1 year ago
How many grams of NH3 are needed to provide the same number of molecules as in 0.35 g of SF6 ?
Strike441 [17]

Answer:

<u />

  • <u>There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.</u>

<u />

Explanation:

Using the molar mass of the chemical formula SF₆ you can find the number of moles of molecules in 0.35 g of such substance. Then, using the molar mass of NH₃, you can find mass in grams corresponding to the same number of molecules.

<u>1. Find the molar mass of SF₆:</u>

Atom   atomic mass          number of atoms   total mass in 1 mole

S           32.065 g/mol                     1                                       32.065 g

F            18.998 g/mol                     6                 6 × 18.998 = 113.988 g

                                                                               =====================

                                                          molar mass of SF₆ =    146.053 g/mol

<u>2. Find the number of moles in 0.35 g of SF₆:</u>

  • number of moles = mass in grams / molar mass
  • number of moles = 0.35 g / 146.053 g / mol = 0.0024 mol

<u>3. Find the molar mass of NH₃:</u>

Atom   atomic mass          number of atoms   total mass 1 mole                

N           14.007 g/mol                     1                                       14.007 g

H             1.008 g/mol                    3               3 × 1.008 g = 113.988 g

                                                                               =====================

                                                         molar mass of NH₃ =    17.031 g/mol

<u />

<u>4. Find the mass in 0.0024 mol of NH₃:</u>

  • mass in grams = number of moles × molar mass

  • mass = 0.0024 mol × 17.031 g/mol ≈ 0.041 grams

<u>5. Conclusion: </u>

There are 0.041 g of NH₃ in the same number of molecules as in 0.35 g of SF₆.

6 0
1 year ago
The lewis structure of pf3 shows that the central phosphorus atom has ________ nonbonding and ________ bonding electron pair(s)
vfiekz [6]
The Lewis structure of PF3 shows that the central phosphorus atom has one non bonding and three bonding electron pairs. In this compound each Phosphorus atom contributes 5 valence electrons while each fluoride contributes 7 valence electrons making a total of 26 valence electrons. The central Phosphorus atom forms single bonds with each of the fluoride atoms. Phosphorus, therefore ends up with a non-bonding pair since the fluoride atoms already have 8 electrons around them. <span />
6 0
1 year ago
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