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ahrayia [7]
2 years ago
6

_________ 1. an allotrope of carbon that is soft and can be used as a lubricant is ______.

Chemistry
1 answer:
dangina [55]2 years ago
8 0
<span>1. An allotrope of carbon that is soft and can be used as a lubricant is </span><span>d. graphite.
</span>Graphite is the most stable allotrope of carbon under standard conditions (pressure and temperature). In graphite carbon atoms have sp2 hybridization, because of that graphite has ability to conduct electricity and heat.

2. The process by which a solid changes directly to a gas without first becoming a liquid is called <span>c. sublimation.
</span>Sublimation is an endothermic process. For example dry ice (carbon(IV) oxide in solid state) is used because of sublimation in nightclubs, fog machines<span>, at </span>theaters<span>, </span>haunted house attractions.

3. In the gaseous state d. halogens form diatomic covalent molecules.
Halogen diatomic molecules (17 group<span> in the </span>periodic table, halogen means "salt producing) in the gaseous state in room temperature are fluorine (F₂) and chlorine (Cl₂). Both molecules have single covalent bond and they are very reactive.

4. When hydrogen reacts with the active metals, it <span>b. gains one electron.
Active metals are I group of Periodic table of elements (alkaline metals). Alkaline metals are </span><span>lithium, sodium, rubidium, potassium, cesium. They have low ionization energy and lose one electron very easy. Compounds with hydrogen with this metals are called hydrides.

5. D</span>ifferent forms of the same element that have different properties because of different atom arrangements are called <span>a. allotropes.
Carbon has many allotropes, but two most important are graphite and diamomd. Graphite has sp2 and diamond has sp3 hybridization of carbon atoms, because of that graphite conduct electricity and diamond not.

6. A</span>t room temperature, most metals are <span>b. solids.
Most metals have strong metallic bond, because strong </span><span>electrostatic attractive force between </span>valence electrons (metals usually have low ionization energy and lose electrons easy) <span>and positively charged </span>metal<span> ions.
</span>They also form <span>crystal lattice and because of that has high melting points.
</span><span>
7. A</span>n allotrope of carbon that is hard and is often used in jewelry is b. diamond.
In diamond carbon atoms<span> are arranged in the </span>face centered cubic<span> crystal structure called a </span>diamond lattice.
Diamond has very strong covalent bonds between carbon atoms and because of that <span>it has the highest </span>hardness<span> and </span>thermal conductivity<span> of any bulk substance. 

8. M</span>etals can be used as wire because they are a. ductile.
Ductility<span> is a measure of a material's (in this example metal) ability to undergo deformation before rupture. For example g</span><span>old is very ductile and can be drawn into a monoatomic wire.</span>
Malleability<span> is a material's ability to deform under </span>compressive<span> stress.
</span>
9. The d. transition elements often occur in nature as uncombined elements.
Uncombined elements are in elemental form and do not attache with other elements. Several transition elements (metals) like gold, silver, rhodium, palladium and platinum are unreactive and <span>are resistant to oxidation and corrosion.</span>
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6) A 0.20 ml CO2 bubble in a cake batter is at 27°C. In the oven it gets
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Answer: The new volume of cake is 1.31 mL.

Explanation:

Given: V_{1} = 0.20 mL,         T_{1} = 27^{o}C

V_{2} = ?,                    T_{2} = 177^{o}C

Formula used to calculate new volume is as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.20 mL}{27^{o}C} = \frac{V_{2}}{177^{o}C}\\V_{2} = 1.31 mL

Thus, we can conclude that the new volume of cake is 1.31 mL.

5 0
2 years ago
Metals with ________ electron configurations characteristically form diamagnetic, square planar complexes.
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Answer:

B

Explanation:

Diamagnetism , paramagnetism and ferromagnetism are terms which are used to describe the magnetic activity of transition metals. These terms helps to know the response the metal will have when placed in a magnetic field. These activities can be discerned from the d-block electronic configuration. If the number of electrons are even, this means they all form a pair and the metal is diamagnetic. If otherwise, there is an unpaired electron which causes the paramagnetic activity of the metal in magnetic field.

To the question, options A-D are diamagnetic but configurations with d8 are the ones that form square planar complexes

8 0
2 years ago
Predict the enthalpy of reaction from the average bond enthalpies for the following reaction: 2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O
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B

Explanation:

8 0
2 years ago
The unsaturated hydrocarbon butadiene (C4H6) dimerizes to 4-vinylcyclohexene (C8H12). When data collected in studies of the kine
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Answer:

The dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

R=k[C_4H_6]^2

Explanation:

2C_4H_6\rightarrow C_8H_{12}

The rate of the reaction ;

R=k[C_4H_6]^x

As given in the question , that graph of time verses \frac{1}{[C_4H_6]} was linear but plots of [C_4H_6] or \ln[C_4H_6]  was curved.

Generally:

Graph of time verses [concentration] for zero order reaction is linear with negative slope.

Graph of time verses \ln [concentration] for secon order reaction is linear with negative slope.

Graph of time verses \frac{1}{[concentration]} for secon order reaction is linear with positive slope.

So, the dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

R=k[C_4H_6]^2

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