C5H12 + 8 O2 → 5 CO2 + 6 H2O
8 molecules of O2 are required.
Answer:
Explanation:
2 H₂(g) + O₂(g) → 2 H₂O(g
2 moles 1 mole 2 mole
50 g of H₂ = 50 /2 = 25 moles of H₂
100 g of O₂ = 100 / 32 = 3.125 moles of O₂
So oxygen is the limiting reagent .
3.125 moles of O₂ will react with 6.25 moles of H₂ to give 6.25 moles of H₂O .
Hence moles of H₂O produced = 6.25 moles .
Answer:
Molarity = 1.93 mol.L⁻¹
Explanation:
Molarity is the unit of concentration used to specify the amount of solute in given amount of solution. It is expressed as,
Molarity = Moles / Volume of Solution ----- (1)
Data Given;
Mass = 11.3 g
Volume = 100 mL = 0.10 L
First calculate Moles for given mass as,
Moles = Mass / M.mass
Moles = 11.3 g / 58.44 g.mol⁻¹
Moles = 0.1933 mol
Now, putting value of Moles and Volume in eq. 1,
Molarity = 0.1933 mol ÷ 0.10 L
Molarity = 1.93 mol.L⁻¹
Answer: Option (b) is the correct answer.
Explanation:
The energy necessary to remove an electron from a gaseous atom or ion is known as ionization energy.
This means that smaller is the size of an atom more amount of energy has to be supplied to it in order to remove the valence electron. This is because in small atom or element there will be strong force of attraction between the nucleus and electrons.
So, high amount of energy has to be supplied to remove the valence electrons.
As electronic configuration of helium is
. So, due to completely filled valence shell it is more stable in nature.
As a result, we need to provide very high amount of energy to remove an electron from a helium atom.
Thus, we can conclude that out of the given options helium element would the first ionization energy of the atom be higher than that of the diatomic molecule.