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1 year ago

The shape of an atomic orbital is associated with

Chemistry

1 answer:

Diano4ka-milaya [45]1 year ago

8 0

The properties of the atomic orbital are actually dependent on the quantum numbers.

size of atomic orbital: governed by the principal quantum number (n)

shape of atomic orbital: governed by the angular momentum quantum number (l)

orientation in space: governed by the magnetic quantum number (ml)

Since we are asked about the shape, hence the correct answer is:

angular momentum quantum number (l)

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Classify each of the following aqueous solutions as a nonelectrolyte, weak electrolyte, or strong electrolyte.

OLEGan [10]

<h3>Answer:</h3>

a) LiClO4 - Strong electrolyte

b) HClO -Weak electrolyte

c) CH3CH2CH2OH - Non-electrolyte

d) HClO3 - Strong electrolyte

e) CuSO4 -strong electrolyte

f) C12H22O11-Non-electrolyte

<h3>Explanation:</h3>

An electrolyte is a substance in an aqueous or molten form which is decomposed by passing an electric current through it. Electrolytes ionize to ions which are responsible for the conduction of electric charge.
Non-electrolytes are substances that do not ionize into cations and anions and thus do not conduct. They include molecular compounds such as gases.
Electrolytes may be weak or strong depending on the level of ionization.
Weak electrolytes are those that undergo partial ionization while strong electrolytes completely ionize.

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1 year ago

When 100 ml of 1.0 M Na3PO4 is mixed with 100 ml of 1.0 M AgNO3,a yellow precipitate forms and Ag+ becomes negligibly small. Whi

jok3333 [9.3K]

Answer:

Option A

Explanation:

Number of millimoles of Na3PO4 = 1 × 100 = 100

Number of millimoles of AgNO3 = 1 × 100 = 100

When 1 mole of Na3PO4 is dissociated we get 3 moles of sodium ions and 1 mole of phosphate ion

When 1 mole of AgNO3 is dissociated, we get 1 mole of Ag+ and 1 mole of NO3-

As Ag+ concentration is negligible, the dissociated Ag+ ion must have form the precipitate with phosphate ion and as number of moles of Ag+ and phosphate ion are same, therefore the concentration of phosphate ion must be negligible

Here as 100 millimoles of Na3PO4 is there, we get 300 millimoles of Na+ and 100 millimoles of PO43-

And as 100 millimoles of AgNO3 is there, we get 100 millimoles of Ag+ and 100 millimoles of NO3-

∴ Increasing order of concentration will be PO43- < NO3- < Na+

4 0

2 years ago

Read 2 more answers

there is a total of seventeen constitutional isomers for the molecular formula c5h13n. draw the skeletal formula of all three co

MAXImum [283]

Amines are derivatives of Ammonia (NH₃) in which atleast one hydrogen atom is replaced by an alkyl group. Amines are further classifies as;

Primary Amines:
In primary amines the nitrogen atom is attached to two hydrogen atoms and one alkyl group.

Secondary Amines:
In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.

Tertiary Amines:
In tertiary amines the nitrogen atom is attached to three alkyl groups, hence it has no hydrogen atom.

Below are three isomers of tertiary amines with molecular formula C₅H₁₃N.

5 0

2 years ago

How do models help scientists predict the polarity of molecules?

yuradex [85]

Answer:There are three main properties of chemical bonds that must be considered—namely, their strength, length, and polarity. The polarity of a bond is the distribution of electrical charge over the atoms joined by the bond. Specifically, it is found that, while bonds between identical atoms (as in H2) are electrically uniform in the sense that both hydrogen atoms are electrically neutral, bonds between atoms of different elements are electrically inequivalent. In hydrogen chloride, for example, the hydrogen atom is slightly positively charged whereas the chlorine atom is slightly negatively charged. The slight electrical charges on dissimilar atoms are called partial charges, and the presence of partial charges signifies the occurrence of a polar bond.

Explanation:

8 0

2 years ago

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Consider the air over a city to be a box 100km on a side that reaches up to an altitude of 1.0 km. Clean air is blowing into the

Mariana [72]

Explanation:

It is known that equation for steady state concentration is as follows.

$C_{a} = \frac{QC}{Q + kV}$

where, Q = flow rate

k = rate constant

V = volume

C = concentration of the entering air

Formula for volume of the box is as follows.

V = $a^{2}h$

= $100 \times 100 \times 1$

= $10000 km^{3}$

Now, expression to determine the discharge is as follows.

Q = Av

= $100 \times 1 \times \frac{4 m}{s} \times \frac{km}{1000 m}$

= 0.4 $km^{3}/s$

And, m (loading) = 10kg/s,

k = 0.20/hr

as 1 $km^3 = 10^{12}$ L (if u want kg/L as concentration)

Now, calculate the concentration present inside as follows.

$C_{in} = \frac{10kg/s}{0.4 km^3/s}$

= 25 $kg/km^3$

Now, we will calculate the concentration present outwards as follows.

$C_{out} = {C_{in}}{(1 + k \times t)}$ ,

and, t = $\frac{V}{Q}$

= 25000 s or 6.94 hr

Hence, $C_{out} = \frac{25}{(1 + 0.20 \times 6.94)}$

= 10.47 $kg/km^3$

Thus, we can conclude that the the steady-state concentration if the air is assumed to be completely mixed is $C_{out} = 10.47 kg/km^3$ and $C_{in} = 25 kg/km^3$ .

4 0

1 year ago