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juin [17]
2 years ago
13

Classify each of the following aqueous solutions as a nonelectrolyte, weak electrolyte, or strong electrolyte.

Chemistry
1 answer:
OLEGan [10]2 years ago
6 0
<h3>Answer:</h3>

a) LiClO4 - Strong electrolyte

b) HClO -Weak electrolyte

c) CH3CH2CH2OH - Non-electrolyte

d) HClO3 - Strong electrolyte

e) CuSO4 -strong electrolyte

f) C12H22O11-Non-electrolyte

<h3>Explanation:</h3>
  • An electrolyte is a substance in an aqueous or molten form which is decomposed by passing an electric current through it. Electrolytes ionize to ions which are responsible for the conduction of electric charge.
  • Non-electrolytes are substances that do not ionize into cations and anions and thus do not conduct. They include molecular compounds such as gases.
  • Electrolytes may be weak or strong depending on the level of ionization.
  • Weak electrolytes are those that undergo partial ionization while strong electrolytes completely ionize.
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An unknown solid is entirely soluble in water. On addition of dilute HCl, a precipitate forms. After the precipitate is filtered
Karo-lina-s [1.5K]

Answer:

Pb(NO3)2

Cd(NO3)2

Na2SO4

Explanation:

In the first part, addition of HCl leads to the formation of PbCl2 which is poorly soluble in water. This is the first precipitate that is filtered off.

When the pH is adjusted to 1 and H2S is bubbled in, CdS is formed. This is the second precipitate that is filtered off.

After this precipitate has been filtered off and the pH is adjusted to 8, addition of H2S and (NH4)2HPO4 does not lead to the formation of any other precipitate.

The yellow flame colour indicates the presence of Na^+ which must come from the presence of Na2SO4.

5 0
1 year ago
5.00 g of hydrogen gas and 50.0g of oxygen gas are introduced into an otherwise empty 9.00L steel cylinder, and the hydrogen is
GenaCL600 [577]
1) Balanced chemical reaction:

2H2 + O2 -> 2H20

Sotoichiometry: 2 moles H2: 1 mol O2 : 2 moles H2O

2) Reactant quantities converted to moles

H2: 5.00 g / 2 g/mol = 2.5 mol

O2: 50.0 g / 32 g/mol = 1.5625 mol

Limitant reactant: H2 (because as per the stoichiometry it will be consumed with 1.25 mol of O2).

3) Products

H2 totally consumed -> 0 mol at the end

O2 = 1.25 mol consumed -> 1.5625 mol - 1.25 mol = 0.3125 mol at the end

H2O: 2.5 mol H2 produces 2.5 mol H2O -> 2.5 mol at the end.

Total number of moles: 0.3125mol + 2.5 mol = 2.8125 mol

4) Pressure

Use pV = nRT
n = 2.8125
V= 9 liters
R = 0.082 atm*lit/K*mol
T = 35 C + 273.15 = 308.15K

p = nRT/V  = 7.9 atm
3 0
2 years ago
Read 2 more answers
The melting point of water is 0°C at 1 atm pressure because under these conditions:
Tems11 [23]

Answer:

The correct answer is option C, that is, ΔS and ΔSsurr for the process H2O (s) ⇒ H2O(l) are equal in magnitude and opposite in sign.

Explanation:

The temperature at which solid state of water get transformed into liquid state is termed as the melting point of 0 °C. It can be shown by the reaction:  

H2O (s) ⇒ H2O (l)

The degree of randomness of a molecule is known as entropy. With the transformation of ice into liquid state, there is an increase in randomness. Thus, the value of entropy becomes positive as shown:  

Entropy change (ΔSsys) = ΔSproduct - ΔSreactant

= (69.9 - 47.89) J mol/K

= 22.0 J mol/K

Therefore, the value of entropy change is positive.  

Now the value of entropy for surrounding ΔSsurr will be,  

ΔSsurr = -ΔHfusion/T  

= -6012 j/mol/273

= -22.0 J/molK

Hence, the value of ΔSsurr and ΔSsys exhibit same magnitude with opposite sign.  

8 0
2 years ago
A column is filled with four different liquids of different densities. A red liquid, a blue liquid, a green liquid, and a purple
zhuklara [117]
4. Blue, Red, Green, Purple

(Lowest densities on the top, highest densities on the bottom)
7 0
2 years ago
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How many molecules are in 70.7 grams of C4H10?
OlgaM077 [116]

Answer:

1.216mol

Explanation:

The molar mass of C₄H₁₀ is (12 x4)+ (1x 10) = 48 + 10 = 58g

1 grams C4H10 is equal to 0.017205129881525 mole.

70.7 grams = 70.7 x 0.017205129881525  = 1.216mol

6 0
2 years ago
Read 2 more answers
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