Answer:
El volumen del cuerpo es el mismo al comienzo de la experiencia.
Explicación:
El volumen del cuerpo es el mismo al principio porque el volumen no cambia si la temperatura permanece igual. Si cambiamos la temperatura i. mi. Al aumentar la temperatura, las moléculas comienzan a expandirse y se produce un aumento de volumen mientras que cuando disminuimos la temperatura, las moléculas de esa sustancia comienzan a contraerse y el volumen de esa sustancia disminuye. Entonces concluimos que el volumen depende de la temperatura.
The answer should be <span>enteropeptidase
</span>
<span>0.127 moles
The formula for nitroglycerin is C3H5N3O9 so let's first calculate the molar mass of it.
Carbon = 12.0107
Nitrogen = 14.0067
Hydrogen = 1.00794
Oxygen = 15.999
C3H5N3O9 = 3 * 12.0107 + 5 * 1.00794 + 3 * 14.0067 + 9 * 15.999 = 227.0829
Now calculate the number of moles of nitroglycerin you have by dividing the mass by the molar mass
2.50 ml * 1.592 g/ml / 227.0829 g/mol = 0.017527 mol
The balanced formula for when nitroglycerin explodes is
4 C3H5N3O9 => 12 CO2 + 10 H2O + O2 + 6 N2
Since all of the products are gasses at the time of the explosion, there is a total of 29 moles of gas produced for every 4 moles of nitroglycerin
Now multiply the number of moles of nitroglycerin by 29/4
0.017527 mol * 29/4 = 0.12707075 moles
Round to 3 significant figures, giving 0.127 moles</span>
The reaction is:
4 PCl3 (g) ---> P4(s) + 6 Cl2(g).
Now, you need to convert the mass of PCl3 into number of moles, for which you use the molar mass of PCl3 in this way:
number of moles = number of grams / molar mass =>
number of moles of PCl3 = 612 g / 137.32 g/mol = 4.4567 moles of PCl3.
Now use the proportion with the ΔH rxn given.
4 mol PCl3 / 1207 kJ = 4.4567 mol / x => x = 4.4567 mol * 1207 kJ / 4 mol = 1,344.8 kJ = 1.34 * 10^3 kJ.
Answer: 1.34 * 10 ^3 kJ (option d)
Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate 
in order to prepare a 0.452 m solution
Explanation:
Molality : It is defined as the number of moles of solute present per kg of solvent
Formula used :
where,
n= moles of solute
Moles of 
= weight of the solvent in g = ?
Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate in order to prepare a 0.452 m solution
